Answer:
the statements the correct one is A
Explanation:
Let's analyze this exercise, vehicles have the same mass and speed, so we can use the momentum impulse ratio
I = ∫ F dt = Δp
the Δp is the same for both cars since they have the same mass and the same speeds, so the momentum is the same in both vehicles
When they indicate that vehicle A was reduced more than vehicle B, this implies that the force acted for a longer time, to have the largest reduction in size, therefore the impact force was less in car A than in car B
Resisting the statements the correct one is A
Answer:
43.2 N
Explanation:
= Wavelength = 0.75 m
f = Frequency = 40 Hz
m = Mass of string = 0.12 kg
L = Length of string = 2.5 m
= Linear density = 
Velocity of wave is given by
The tension in string is given by
The tension in the string is 43.2 N
Well if the encounter is good then that would be great to write about!!
This is an example of Uniform Speed
EXPLANATION
Uniform Speed => no change in speed
Uniform Accelerations Speed => There is a change in speed, but the acceleration remains the same.
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The force (F) of attraction or repulsion between two point charges (Q1 and Q2) is given by the following rule:
F = <span>(k * q1 * q2) / (r^2) where:
</span>q1 and q2 are the charges
k is coulomb's constant = 9 x 10^9<span> N. m</span>2/ C<span>2
</span>r is the distance between the two charges.
Applying the givens in the mentioned equation, we find that:
F = (9 x 10^9<span> x 0.07 x 10^6 x 2) / (0.0108)^2 = 1.08 x 10^19 n </span>
