<span><span> y2(q-4)-c(q-4)</span> </span>Final result :<span> (q - 4) • (y2 - c)
</span>
Step by step solution :<span>Step 1 :</span><span>Equation at the end of step 1 :</span><span><span> ((y2) • (q - 4)) - c • (q - 4)
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span> y2 • (q - 4) - c • (q - 4)
</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out q-4
After pulling out, we are left with :
(q-4) • (<span> y2</span> * 1 +( c * (-1) ))
Trying to factor as a Difference of Squares :
<span> 3.2 </span> Factoring: <span> y2-c</span>
Theory : A difference of two perfect squares, <span> A2 - B2 </span>can be factored into <span> (A+B) • (A-B)
</span>Proof :<span> (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 <span>- AB + AB </span>- B2 =
<span> A2 - B2</span>
</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication.
Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.
Check : <span> y2 </span>is the square of <span> y1 </span>
Check :<span> <span> c1 </span> is not a square !!
</span>Ruling : Binomial can not be factored as the difference of two perfect squares
Final result :<span> (q - 4) • (y2 - c)
</span><span>
</span>
Answer:
300 grams
Step-by-step explanation:
To find the total number of carbohydrates, you need to find what fraction 6 is of 100, so you can do 100/6, but I just did 18* 100/6 right away, so that you can find 18* the fraction that 6 is of 100. The answer that I got is 300 grams. Hope this helps!
1.500 since 45 rounds to 50
Answer: The central limit theorem tells us that when random samples are chosen the results tend to approach a normal distribution.
The basic idea is that the more random samples that you select, the closer you should get to the mean. In most cases, 30 or more samples is regarded as a large enough sample to get close to the mean. Our sample is 48, so we should be close to the mean.
You're answer is D.
-3/-3(2)-9
1(2)-9
2-9
7
so it is D
