Question

A multi-plattered hard disk is divided into 1100 sectors and 40,000 cylinders. There are six platter surfaces. Each block holds 512 bytes. The disk is rotating a rate of 4800 rpm. The disk has an average seek time of msec. What is the total capacity of this disk

Answer 1

Answer:

total capacity  = 135,168,000,000 bytes

Explanation:

given data

hard disk divided = 1100 sectors

cylinders = 40,000

block holds = 512 bytes

rotating  rate = 4800 rpm

consider average seek time = 12 msec

to find out

total capacity of this disk

solution

total capacity of this disk are express as

total capacity  = hard disk divided × cylinder  block holds × average seek time ÷ 2

put here value we get

total capacity  =  1100 × 40000 × 512 × 6

total capacity  = 135,168,000,000 bytes