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Marat540 [252]
3 years ago
15

Where conventional relays, contactors and switches, which have arcing contacts, are installed in Class I, Division 1 and 2 locat

ions, they must be enclosed in ? .
Physics
1 answer:
solmaris [256]3 years ago
7 0

Answer:

They must be enclosed in explosion proof housing or general-purpose housing (as per NEC Regulations)

Explanation:

It is important to know what are Class I, Division 1 and 2 locations.

Class I: includes those industries or places where flammable gases exists and there are chances of explosions.

Division 1: Those places where hazard can happen under normal operating conditions

Division 2: Those places where hazard can happen under abnormal conditions.

The conventional relays, contactors and switches cause arcing when they operate and this is a completely normal phenomenon but with respect to these categories, it is very dangerous to operate such electrical devices without any precaution.

Therefore industries are required by the regulatory authorities to install  explosion proof housing to enclose conventional relays, contactors and switches to avoid any explosion or hazard. General-purpose housing can also be used given that it follows the regulations provided by the NEC or any other regulatory authority.

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The value of acceleration due to gravity is less at the top of Mount Everest then that in the terai reason, why?​
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The value of acceleration due to gravity is greater in terai than in mountain. In terai region the radius of earth is less as it lies close to the centre of the earth. Thus, the value of g is more in terai region.

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2 years ago
Kuiper Belt objects are composed of which substances? Select all that apply.
levacccp [35]
IM sure there is C, D, and E in kuiper belts, but not really sure of silicon and iron

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True of false metals like copper are sometimes used to fill cavities in teeth
vovikov84 [41]
Yes. Copper, mercury, and tin are all used to fill in cavities. 
4 0
3 years ago
which of the glass lenses above, when placed in air, will cause rays of light (parallel to the central axis) to converge?
777dan777 [17]

Convex lenses when placed in the air, will cause rays of light (parallel to the central axis) to converge.

Converging lenses, commonly referred to as convex lenses, have thicker centers and narrower upper and lower margins. The edges are outwardly curled. This lens has the ability to concentrate a beam of parallel light rays coming from the outside onto a spot on the opposite side of the lens.

The image created is referred to be a genuine image when it is inverted relative to the object. On a screen, this kind of image can be recorded. When the object is positioned at a point farther than one focal length from the lens, a converging lens creates a true image.

A virtual image is one that cannot be produced on a screen and is formed when the image is upright in relation to the object. When an item is positioned within one focal length of a converging lens, a virtual image is created. It creates an enlarged image of the object on the same side of the lens as the image. It serves as a magnifier.

Learn more about the convex lens here:

brainly.com/question/12847657

#SPJ4

3 0
1 year ago
MARKING BRAINLIST | Which situation below would have the STRONGEST gravitational force between them?
maks197457 [2]

Case d) has the strongest gravitational force

Explanation:

The magnitude of the gravitational force between two objects is given by the equation:

F=G\frac{m_1 m_2}{r^2}

where :

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

a) For this pair of objects:

m1 = 10 kg

m2 = 2 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(2)}{30000^2}=1.48\cdot 10^{-18}N

b) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 30 km = 30,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{30000^2}=7.41\cdot 10^{-18}N

c) For this pair of objects:

m1 = 2 kg

m2 = 2 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(2)(2)}{10000^2}=1.33\cdot 10^{-17}N

d) For this pair of objects:

m1 = 10 kg

m2 = 10 kg

r = 10 km = 10,000 m

So the gravitational force is

F=(6.67\cdot 10^{-11})\frac{(10)(10)}{10000^2}=6.67\cdot 10^{-17}N

Therefore, the  strongest gravitational force is in case d).

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

6 0
3 years ago
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