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2 years ago

Answer the question answer question

Mathematics

2 answers:

Rashid [163]2 years ago

8 0

K = (7.5, 2.25).

- Hope this helps.

vlada-n [284]2 years ago

6 0

Answer:

i believe its (7,2.5)

Step-by-step explanation:

Maybe im wrong but i hope it helped

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Finish solving the system of equations –9.5x – 2.5y = –4.3 and 7x + 2.5y = 0.8 using the linear combination method.

trasher [3.6K]

Answer:

The value of x is 1.4 and y is -3.6

Step-by-step explanation:

The steps are :

$- 9.5x - 2.5y = - 4.3 - - - (1)$

$7x + 2.5y = 0.8 - - - (2)$

$(1) + (2)$

$- 9.5x + 7x - 2.5y + 2.5y = - 4.3 + 0.8$

$- 2.5x = - 3.5$

$x = \frac{7}{5} \: or \: 1.4$

$substitute \: x = 1.4 \: into \: (2)$

$7(1.4) + 2.5y = 0.8$

$9.8 + 2.5y = 0.8$

$2.5y = - 9$

$y = - \frac{18}{5} \: or \: - 3.6$

3 0

2 years ago

Please help idek know what this is asking me.....

nadya68 [22]

Answer:

I think The answer is...C

3 0

2 years ago

Data from 14 cities were combined for a 20-year period, and the total 280 city-years included a total of 107 homicides. After fi

dlinn [17]

Answer:

a) P(0) = 0.6824

b) P(1) = 0.2608

c) P(2) = 0.0498

d) P(3) = 0.00635

Step-by-step explanation:

Number of units (n) in the data, n = 280

Total number of events, k = 107

The probability using Poisson probabilities is calculated using the formula;

P(x) = $\frac{e^{-\lambda}\lambda^x}{x!}$

here,

Poisson parameter, λ = $\frac{107}{280}$

Thus,

a) P(0) = $\frac{e^{-\frac{107}{280}}(\frac{107}{208})^0}{0!}$

P(0) = 0.6824

b) P(1) = $\frac{e^{-\frac{107}{280}}(\frac{107}{280})^1}{1!}$

P(1) = 0.2608

c) P(2) = $\frac{e^{-\frac{107}{280}}(\frac{107}{280})^2}{2!}$

P(2) = 0.0498

d) P(3) = $\frac{e^{-\frac{107}{280}}(\frac{107}{280})^3}{3!}$

P(3) = 0.00635

7 0

2 years ago

Expand 9(2n+3)<br><br> Pls help

jenyasd209 [6]

Answer:

18n + 27

Step-by-step explanation:

9(2n+3)

18n + 27

6 0

2 years ago

How did you slove the problem and what's the answer

andrey2020 [161]

Answer: b) 2x² - 5x - 3

<u>Step-by-step explanation:</u>

Distribute each term in the first parenthesis into the second term and then add like terms.

(2x + 1)(x - 3)

= 2x(x - 3) + 1(x - 3)

= 2x² - 6x + x - 3

= 2x² - 5x - 3

7 0

3 years ago