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Harrizon [31]
4 years ago
15

What happens when a blaring siren moves away from you

Physics
1 answer:
Anit [1.1K]4 years ago
4 0
It gets quieter as the sound waves have to travel further and so the volume decreases
You might be interested in
2. A new racecar track is being created, and the owners want the cars to complete 10
jeka57 [31]

Answer:

0.45 miles

Explanation:

since, car will be running on the edge of track, distance covered in one lap by car will be equal to circumference of track.\

we will use value of pi as 22/7

Circumference for any circular shape is given by \piD\pi D

Hence, in one lap \pi D distance will be covered

in 7 laps 7 \pi D distance will be covered.

but is given that 7 laps should be equal to 10 miles

so 10 miles will be equal to 7\pi D

7\pi D= 10 \ miles\\=> 7*(22/7)* D= 10 \ miles\\=> 22D = 10 \ miles\\=> D = 10/22 \ miles\\=> D = 0.45 \ miles

Thus, diameter of track will be 0.45 miles to meet the requirement.

3 0
3 years ago
Alligators and other reptiles don't use enough metabolic energy to keep their body temperatures constant. they cool off at night
drek231 [11]
To compute for the heat, Q needed to be absorbed or released,  we need

Q = mc\Delta T

where m is the mass of the alligator, \Delta T is the change in temperature, and c is the specific heat of the alligator's body. Plugging in all the information we have,

Q = (300 kg)(3400 kJ/K)(30-25) = 5100000 J

Recall that 1 Watt = 1 J/s, thus time needed to absorb radiation from the sun is

t = \frac{Q}{W}\\ t = 4250 seconds

That means it takes 4250 seconds for the alligator to warm up to be able to absorb the radiation from the sun.

Answer: 4250 seconds



4 0
4 years ago
In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested travelin
Vika [28.1K]

Answer:

Explanation:

Let the required velocity of rocket be v .

We shall use the formula of time dilation to find the velocity of rocket .

t = \frac{t'}{\sqrt{1-\frac{v^2}{c^2} } }

t = 430

t' = 38

430=\frac{38}{\sqrt{1-\frac{v^2}{c^2} } }

\sqrt{1-\frac{v^2}{c^2} } }=\frac{38}{430}

1-\frac{v^2}{c^2} = .0078

\frac{v^2}{c^2} =.9922

\frac{v}{c} = .996

v  = .996 x 3 x 10⁸ m /s

= 2.988 x 10⁸ m /s

B )

Kinetic energy of rocket

= 1/2 m v²

= .5 x 20000 x (2.988 x 10⁸ )²

= 8.9 x 10²⁰ J .

C )

This energy is 8.9 times the energy requirement of United states in the year 2005 .

7 0
3 years ago
School homework about multiplying fractions <br><br>worth 30 brainly points​
RoseWind [281]

Answer:

Explanation:

1. \frac{1}{3} x \frac{6}{7} = \frac{6}{21}

          = \frac{2}{7}

b. \frac{6}{8} + \frac{4}{9} = \frac{24}{72}

            = \frac{1}{3}

c. \frac{10}{15} x \frac{3}{4} = \frac{30}{60}

            = \frac{1}{2}

d. \frac{7}{10} of \frac{5}{10} = \frac{7}{10} x \frac{5}{10}

                = \frac{35}{100}

                = \frac{7}{20}

e. \frac{3}{8} of \frac{4}{6} = \frac{3}{8} x \frac{4}{6}

            = \frac{12}{48}

            = \frac{1}{4}

f. \frac{7}{12} of \frac{9}{14} = \frac{7}{12} x \frac{9}{14}

              = \frac{63}{168}

              = \frac{3}{8}

2. \frac{22}{6} x \frac{3}{11} = \frac{66}{66}

              = 1

b. \frac{15}{6} x \frac{4}{5} = \frac{60}{30}

             = 2

c. \frac{25}{8} x \frac{4}{10} = \frac{100}{80}

              = \frac{5}{4}

d. \frac{33}{12} x \frac{4}{15} = \frac{132}{180}

             = \frac{11}{15}

4 0
3 years ago
An aluminum wire having a cross-sectional area equal to 3.00 10-6 m2 carries a current of 7.00 A. The density of aluminum is 2.7
Natali [406]

Answer:

Vd = 2.42 ×10⁻⁴ m/s

Explanation:

Given: A = 3.00×10⁻⁶ m², I = 7.00 A, ρ = 2.70 g/cm³

To find Drift Velocity Vd=?

Sol

the formula is Vd = I/nqA             (n is the number of charge per unit volume)

n = No. of electron in a mole ( Avogadro's No.) / Volume

Volume = Molar mass / density   ( molar mass of Al =27 g)

V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³

n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)

n= 6.02 × 10 ²⁸

Now

Vd = (7A) / (  6.02 × 10 ²⁸ ×  1.6 × 10⁻¹⁹ C ×  3.00×10⁻⁶ m²)

Vd = 2.42 ×10⁻⁴ m/s

6 0
3 years ago
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