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White raven [17]
3 years ago
6

A 25.0g tin sample was placed in boiling water at 99.5 C until it had the same temperature. Afterwards, the tin sample was place

d in room temperature water. If the tin sample lost 399.4J of heat and its final temperature was 24.5 C, what is the specific heat of tin?
Chemistry
1 answer:
MrMuchimi3 years ago
7 0

Answer : The specific heat of tin is, 0.213 J/g.K

Explanation :

Formula used :

q=m\times c\times (T_{final}-T_{initial})

where,

q = amount of heat lost = -399.4 J

c = specific heat capacity of tin = ?

m = mass of tin = 25.0 g

T_{final} = final temperature = 24.5^oC=273+24.5=297.5K

T_{initial} = initial temperature = 99.5^oC=273+99.5=372.5K

Now put all the given values in the above formula, we get:

-399.4J=25.0g\times c\times (297.5-372.5)K

c=0.213J/g.K

Therefore, the specific heat of tin is, 0.213 J/g.K

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