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3 years ago

For the reaction N2(g) + 3H2(g) 2NH3(g), what will happen if more nitrogen gas is added?

Chemistry

2 answers:

vova2212 [387]3 years ago

4 0

Answer : The equilibrium will shift in the right direction or product side.

Explanation :

Le-Chatelier's principle : This principle states that if any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If the concentration on reactant side increases then the equilibrium will shift in the direction where decrease the concentration of reactant. Thus, the equilibrium will shift in the right direction or product side.

The given chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

As per question, if more amount nitrogen gas is added that means amount of reactant increases then the equilibrium will shift in the direction where decrease the amount of $N_2$ takes place. Thus, the equilibrium will shift in the right direction or product side.

Hence, the equilibrium will shift in the right direction or product side.

skad [1K]3 years ago

3 0

The reaction will shift toward the products.

Adding more reactant will shift the reaction to the product.

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In the following chemical reaction between H_2 and Cl_2 to produce HCl, what is the mass of HCl produced and leftover reactants

ira [324]

Answer: The total amount of leftover reactants and HCl is 12.79 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For hydrogen gas:

Given mass of hydrogen gas = 0.36 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrogen gas}=\frac{0.36g}{2g/mol}=0.18mol$

For chlorine gas:

Given mass of chlorine gas = 12.41 g

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

$\text{Moles of chlorine gas}=\frac{12.41g}{71g/mol}=0.175mol$

The chemical equation for the reaction of hydrogen gas and chlorine gas is:

$H_2+Cl_2\rightarrow 2HCl$

By Stoichiometry of the reaction:

1 moles of chlorine gas reacts with 1 mole of hydrogen gas

So, 0.175 moles of chlorine gas will react with = $\frac{1}{1}\times 0.175=0.175mol$ of hydrogen gas

As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, chlorine gas is considered as a limiting reagent because it limits the formation of product.

Moles of excess reactant left (hydrogen gas) = [0.18 - 0.175] = 0.005 moles

By Stoichiometry of the reaction

1 moles of chlorine gas produces 2 moles of HCl

So, 0.175 moles of chlorine gas will produce = $\frac{2}{1}\times 0.175=0.350$ moles of HCl

Now, calculating the mass of hydrogen gas left and HCl from equation 1, we get:

For hydrogen gas:

Molar mass of hydrogen gas = 2 g/mol

Moles of excess hydrogen gas = 0.005 moles

Putting values in equation 1, we get:

$0.005mol=\frac{\text{Mass of excess hydrogen gas}}{2g/mol}\\\\\text{Mass of excess hydrogen gas}=(0.005mol\times 2g/mol)=0.01g$

For HCl:

Molar mass of HCl = 36.5 g/mol

Moles of HCl = 0.350 moles

Putting values in equation 1, we get:

$0.350mol=\frac{\text{Mass of HCl}}{36.5g/mol}\\\\\text{Mass of HCl}=(0.350mol\times 36.5g/mol)=12.78g$

Total mass of HCl and leftover reactants = [12.78 + 0.01] = 12.79 g

Hence, the total amount of leftover reactants and HCl is 12.79 grams

7 0

4 years ago

Consider the insoluble compound silver bromide , AgBr . The silver ion also forms a complex with ammonia . Write a balanced net

Degger [83]

Answer:

- $AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)$

- $K=1.2x10^{-5}$

Explanation:

Hello,

In this case, by considering the dissolution of silver bromide:

$AgBr(s)\rightleftharpoons Ag^+(aq)+Br^-(aq) \ \ \ Ksp=[Ag^+][Br^-]=7.7x10^{-13}$

And the formation of the complex:

$Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)\ \ \ Kf=\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}=1.6x10^7$

We obtain the balanced net ionic equation by adding the aforementioned equations:

$AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)+Ag^+(aq)\\\\AgBr(s)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-(aq)$

Now, the equilibrium constant is obtained by writing the law of mass action for the non-simplified net ionic equation:

$AgBr(s)+Ag^+(aq)+2NH_3(aq)\rightleftharpoons Ag(NH_3)_2^+(aq)+Br^-+Ag^+\\\\K=[Ag^+][Br^-]*\frac{[Ag(NH_3)_2^+]}{[Ag^+][NH_3]^2}$

So we notice that the equilibrium constant contains the solubility constant and formation constant for the initial reactions:

$K=Ksp*Kf=7.7x10^{-13}*1.6x10^{7}\\\\K=1.2x10^{-5}$

Best regards.

4 0

3 years ago

How does the Troposphere (atmosphere where weather takes place) affect the hydrosphere?

Marizza181 [45]

Answer: Atmosphere - Atmosphere - Troposphere: The lowest portion of the atmosphere is the troposphere, a layer where temperature generally decreases with height. This layer contains most of Earth’s clouds and is the location where weather primarily occurs. The lower levels of the troposphere are usually strongly influenced by Earth’s surface.

Explanation:

4 0

3 years ago

Why does chemical changes lead to the formation of compounds.Justify

Rudiy27

Answer:

The addition of energy through the chemical reaction when substance combines and gets decomposed.

Explanation:

Chemical changes take place when the substance combines with some other to form a chemical synthesis and gets alternatively decomposed into 2 different substances through chemical reactions.

As when the chemical reactions occur the atoms rearrange themselves. As these are accompanied by the energy changes.

Such as those of sodium and water to produce sodium hydroxide and hydrogen. The chemical changes are found in organic, inorganic, and biochemical changes.

6 0

3 years ago

The pyruvate dehydrogenase complex is subject to allosteric control, especially inhibition by reaction products. From the list b

Ray Of Light [21]

Answer:

The correct option is B

b. Phosphorylation by a kinase using ATP (which turns the complex off) and dephosphorylation by a phosphatase (which turns the complex on).

Explanation:

The pyruvate dehydrogenase complex is described as a complex having many enzymes that catalyse decarboxylation of pyruvate by oxidation to yield NADH and acetyl‐CoA, which makes the influx of acetyl-coA from glycolysis to increase into the Krebs cycle.

It can be found in the mitochondrial matrix and pyruvate which is conveyed through enzyme Pyruvate Translocase to PDH complex.

Regulation of pyruvate dehydrogenase complex occured through allosteric effectors as well as phosphorylation.the main regulatory processes controlling pyruvate dehydrogenase's activity in eukaryotes such as plants and animals Phosphorylation is by a kinase using ATP which first turns the complex off and the later dephosphorylation by a phosphatase which turns the complex on

7 0

3 years ago