Looking at this equation P= (pa*pb)/ (pa+(pb-pa)) ya where pa=vap press a and ya= vap composition a and P= total pressure,it relates vapor pressure mixture to vapor composition. This is derived using the combination of Dalton's and Raoult's laws.
Molar mass Li2CO3 = 73.89 g/mol
Mol Li2CO3 = 67.5/73.89 =0.91 mol
Mol LiOH = 1.82 mol
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Answer:
They meet at the distance of 32.5 cm
Explanation:
The rate of diffusion is inversely proportional to the molar mass of gases.
If diffusion is represented as d and mass of gases as M. Then , rate is given as:

For , two gases

First , Calculate the ,molar mass of each gas :
CH4 = 1 (mass of C) + 4(mass of H)
= 1(12)+4(1)
= 12 + 4 = 16 gram
M1 = 16 gram
C4H8 = 4(mass of C) + 8(Mass of H)
= 4(12) + 8(1)
= 48 + 8
M2 = 56 grams
d1 is diffusion of CH4
d2 = diffusion of C4H8

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This means CH4 diffuse 1.87 times faster than C4H8
Now, the mathematical part
If velocity of C4H8 = 1 cm/sec , then velocity of CH4 = 1.87 cm/sec
v1 = 1.87 cm/sec
v2 = 1 cm/sec
Let both meet at time "t". If distance travelled by CH4(s1) = x , then remaining(s2) distance (50-x) is travelled by C4H8
(see the attached image)

since both meet at same time so t = constant.


on solving for x we get,
x = 17.42 cm
from the other side the distance is (50 - x)
= 50 - 17.42 = 32.5 cm
<u>Answer</u>:-
When the reaction takes place Ca is reduced or is an oxidizing agent.
Reaction:
Ca + 2Cl =CaCl2
Note: There is a +2 charge on Ca(Calcium) and -1 charge on each Cl-atom(Chlorine atom) hence the charges are cancelled. Therefore, the total charge on the whole compound is zero.
Explanation:-
• Reduction: gain of electron/electrons
gain of hydrogen
loss of oxygen
Oxidation: gain of oxygen
loss of hydrogen
loss of electron/electrons.
• Oxidizing agent/reduced
Reducing agent/oxidized
• The molecule that is oxidized loses an electron and the molecule that is reduced gains the electron that was lost by the oxidized molecule.