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lubasha [3.4K]
4 years ago
15

How is mercury barometer constructed ?​

Physics
1 answer:
olganol [36]4 years ago
4 0

Answer:

A  mercury barometer is a device use to measure stomspheric pressure and is constructed as following:

  • A mercury barometer requires a tube which has one close end, and one open end.
  • Tube is placed upside down in a beaker in such a way so that one end open in the beaker and the other remain outside of the beaker.
  • The barometric liquid (mercury) is then filled in the tube by pouring mercury liquid in the beaker.

The position of tube creates vacuum between the closed end of the tube and liquid surface and the Mercury has high density that is why used as the liquid to measure pressure.

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What physical property makes the red light different from blue light, or radio waves different from microwaves?​
inna [77]

Only their wavelength does.

Blue light waves have only roughly half the wavelength of red light waves, and the so-called "microwaves" are the radio waves with the shortest wavelengths.

4 0
3 years ago
Read 2 more answers
Calculate the location xcm of the center of mass of the Earth-Moon system. Use a coordinate system in which the center of the Ea
Jet001 [13]

Answer:

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

Explanation:

Let suppose that planet and satellite can be treated as particles. The masses of Earth and Moon (m_{E}, m_{M}) are 5.972\times 10^{24}\,kg and 7.349\times 10^{22}\,kg, respectively. The distance between centers is 384,403 kilometers. The location of the center of mass can be found by using weighted averages:

\bar x = \frac{x_{E}\cdot m_{E}+x_{M}\cdot m_{M}}{m_{E}+m_{M}}

If x_{E} = 0\,km and x_{M} = 384,403\,km, then:

\bar x = \frac{(0\,km)\cdot (5.972\times 10^{24}\,kg)+(384,403\,km)\cdot (7.349\times 10^{22}\,kg)}{5.972\times 10^{24}\,kg+7.349\times 10^{22}\,kg}

\bar x = 4.673\,km

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

8 0
3 years ago
The gold has a density of 19300 kg/m3 calculate the mass of one gold bar 1= 2.54cm
icang [17]
Fair enough, but you'll have to tell us the volume of the bar first.
5 0
3 years ago
A sky diver, with parachute unopened, falls 625 m in 15.0 s. Then she opens her parachute and falls another 362 m in 139 s. What
Jobisdone [24]

Answer:

v_{avg} = 6.41 m/s

Explanation:

Average velocity is defined as the ratio of total displacement of the motion and total time taken in that motion

here we know that initially the sky diver drops without opening parachute by total displacement 625 m

then she open her parachute and drop another 362 m

so first it took time t = 15 s to drop without open parachute

then it took t = 139 s to drop next displacement

so here total displacement is given as

d = 625 m + 362 m

total time is given as

t = 15 s + 139 s

so average velocity is given as

v_{avg} = \frac{625 + 362}{15 + 139}

v_{avg} = 6.41 m/s

4 0
3 years ago
By what factor must the amplitude of a sound wave be decreased in order to decrease the intensity by a factor of 3?
s344n2d4d5 [400]

Answer:

Amplitude is decreased by a factor of \sqrt3 if intensity is decreased by a factor of 3.

Explanation:

Intensity of a sound wave is directly proportional to the square of its amplitude.

Therefore, if intensity is I and amplitude is A, then

I=kA^2, where, k is constant of proportionality.

Now, if intensity of sound wave is decreased by a factor of 3. So,

New intensity is, I_{new}=\frac{I}{3}

I_{new}=kA_{new}^2\\\frac{I}{3}=kA_{new}^2

Plug in kA^2 for I. This gives,

\frac{kA^2}{3}=kA_{new}^2\\A_{new}^2=\frac{A^2}{3}\\A_{new}=\sqrt{\frac{A^2}{3}}=\frac{A}{\sqrt{3}}

Therefore, amplitude is decreased by a factor of \sqrt3.

4 0
3 years ago
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