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4 years ago

13

A family pool holds 10,000 gallons of water how many cubic meters is this

2 answers:

LenKa [72]4 years ago

8 0

10,000 gallons of water = 37.85 cubic meters of water

ruslelena [56]4 years ago

3 0

4959167 is how many cubic meters in 10,000 gallons of water

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3 years ago

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Objects with masses of 235 kg and a 535 kg are separated by 0.330 m. (a) find the net gravitational force exerted by these objec

saul85 [17]

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3 years ago

What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a p

irga5000 [103]

The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

The given parameters;

<em>Pressure on the 13 th floor, P₁ = 35 PSI</em>
<em>Distance between each floor, d = 10 ft</em>

The vertical pressure of the water is calculated as follows;

$P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\$

The vertical height of the first floor from the 13th floor = 130 ft

The vertical height of the 13 ft floor = 10 ft

$P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI$

Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.

Learn more about vertical height and pressure here: brainly.com/question/15691554

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2 years ago

How many cups of water should you drink in a day?

Harrizon [31]

Answer:

about 2.7liters for women and 3.7liters for men

Explanation:

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3 years ago

A vertical spring stretches 4.0 cm when a 12-g object is hung from it. The object is replaced with a block of mass 28 g that osc

marin [14]

Answer:

Time period of the osculation will be 0.0671 sec

Explanation:

It is given a vertical spring is stretched by 4 cm

So change in length of the spring x = 4 cm = 0.04 m

Mass which is hung from it m = 12 gram = 0.012 kg

Sprig force will be equal to weight of the mass

So $kx=mg$

$k\times 0.04=0.012\times 9.8$

k = 244.7 N/m

Now new mass is m = 28 gram = 0.028 kg

So time period with new mass will be

$T=2\pi \sqrt{\frac{m}{k}}$

$=2\times 3.14 \sqrt{\frac{0.028}{244.7}}=0.0671sec$

4 0

3 years ago