Answer:
the speed of the car at the top of the vertical loop
the magnitude of the normal force acting on the car at the top of the vertical loop
Explanation:
Using the law of conservation of energy ;
The magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:
Answer:
a = 5.5 [m/s²]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the force is equal to the product of mass by acceleration.
ΣF =m*a
where:
F = Force [N] (units of Newtons)
m = mass = 20 [kg]
a = acceleration [m/s²]
Let's take the force of 230 [N] as positive, in this way the other force will be negative, by pointing in the opposite direction.
Answer:231.16 N/C
Explanation:
Given
Electric Flux
Area(A)
Given Field point above
Therefore angle between Area vector Electric Field =90-31.6=
We know that Flux is given by
E=231.16 N/C
Answer:
27.95[kW*min]
Explanation:
We must remember that the power can be determined by the product of the current by the voltage.
where:
P = power [W]
V = voltage [volt]
I = amperage [Amp]
Now replacing:
Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]