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Leno4ka [110]
3 years ago
10

Imagine you have 1 kg each of iron, glass, and water, and all three samples are at 10°C. Rank the samples from least to greatest

amount of energy transferred by heat if each sample increases in temperature by 20°C.rank from 1 the least and 3 the greatest please
Physics
1 answer:
ddd [48]3 years ago
6 0

Answer:

(From the least to the greatest) Glass < Iron < Water

Explanation:

The greater the specific heat of the material, the greater the amount of heat needed to increase temperature. Specific heats of each material are presented below:

Iron (Rank 2)

450\,\frac{J}{kg\cdot K}

Glass (Rank 1)

0.8\,\frac{J}{kg\cdot K}

Water (Rank 3)

4186\,\frac{J}{kg\cdot K}

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A thin, uniform rod is bent into a square of side length a. If the total mass is M, find the moment of inertia about an axis thr
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The  moment of inertia about an axis through the center and perpendicular to the plane of the square is

    I_s =  \frac{Ma^2}{3}

Explanation:

From the question we are told that

   The length of one side of the square is  a

   The total mass of the square is  M

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    m_1 = \frac{M}{4}

Generally the moment of inertia of one side of the square is mathematically represented as

        I_g =  \frac{1}{12}  *  m_1 * a^2

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Now substituting for  m_1

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       I _g=  \frac{1}{12}  *  \frac{M}{4} * a^2

Now according to  parallel-axis theorem the moment of inertia of one side of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

      I_a =  I_g + m [\frac{q}{2} ]^2

=>    I_a =  I_g + {\frac{M}{4} }* [\frac{q}{2} ]^2

substituting for I_g

=>    I_a =  \frac{1}{12}  *  \frac{M}{4} * a^2 + {\frac{M}{4} }* [\frac{q}{2} ]^2

=>    I_a = \frac{Ma^2}{48} + \frac{Ma^2}{16}

=>    I_a = \frac{Ma^2}{12}

Generally the moment of inertia of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

      I_s = 4 * I_a

=>   I_s = 4 * \frac{Ma^2}{12}

=>   I_s =  \frac{Ma^2}{3}

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