6 J is the impulse caused by the change in velocity of 2 kg box from 2 m/s to 5 m/s.
Answer:
The magnitude of impulse is 6 J.
Explanation:
Impulse is the force acting on any object for a given time interval. As force is equal to the product of mass and acceleration and acceleration is the rate of change of velocity with time. Then the product of force with time interval will be equal to the product of mass with change in velocity.
F = m a = 
FΔt = mΔv
Impulse = FΔt=mΔv
As the mass of box is given as 2 kg and the velocity changes from 2 m/s to 5 m/s, then the impulse = 2 × (5-2) = 2 ×3 =6 J
So 6 J is the impulse caused by the change in velocity of 2 kg box from 2 m/s to 5 m/s.
Answer:
1. B
2. B
3. D
4. A
Hope this was correct! A lot of the answers are already in the article itself and the wording is just different. I suggest now that for information retainment, you read the article again with the correct points in mind and see if you can spot the points where the answers are stated!
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Answer:
9(3x-2y)
Explanation:
27x-18y, the common factor here is 9
9(3x-2y)
Gauss law states that the electric flux through any closed
surface is proportional to the net electric charge inside the surface. This is
expressed mathematically in the form of:
Φ = Q / εo
Where,
Φ = the electric flux = unknown (which we have to find for)
Q = the net electric charge = 5.0 µC = 5 E-6 C
εo = the permittivity of free space = a constant value =
8.85 E-12 C^2 / N m^2
Plugging in the values
into the equation will result in:
Φ = 5 E-6
C / (8.85 E-12 C^2 / N m^2)
Φ = 564,971.75 Wb = <span>5.6 x
10^5 Wb </span>