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3 years ago

9

The Mariana trench is located in the Pacific Ocean at a depth of about 11 000 m below the surface of the water. The density of s

eawater is 1025 kg/m3. (a) If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.280 m)? (b) For comparison, determine the weight of a jetliner whose mass is 2.44 × 105 kg.

1 answer:

Illusion [34]3 years ago

7 0

Answer:

A) 27209506.5 N

B) 2393640 N

The force on the underwater vehicle is about 11.37 times the weight of the jetliner for comparison.

Explanation:

Force du to depth of water is

F = pghA

P = density of salt water = 1025 kg/m3

g = acceleration due to gravity 9.81 m/s2

h = depth of water 11000 m

A = area pressure acts

Area = ¶r^2 = 3.142 x 0.280^2 = 0.246 m^2

Therefore

F = 1025 x 9.81 x 11000 x 0.246

= 27209506.5 N

Weight of a jetliner with mass 2.44 × 10^5 kg is,

2.44×10^5 x 9.81 = 2393640 N

The force on the underwater vehicle is about 11.37 times the weight of the jetliner for comparison.

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Two loudspeakers are placed on a wall 2 m apart. A listener stands directly in front of one of the speakers, 81.7 m from the wal

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Answer:

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Explanation:

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The path difference of the sound wave that is getting to the listener is mathematically represented as

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The phase difference is mathematically represented as

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substituting value

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Part b)

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