1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natalka [10]
3 years ago
9

The Mariana trench is located in the Pacific Ocean at a depth of about 11 000 m below the surface of the water. The density of s

eawater is 1025 kg/m3. (a) If an underwater vehicle were to explore such a depth, what force would the water exert on the vehicle's observation window (radius = 0.280 m)? (b) For comparison, determine the weight of a jetliner whose mass is 2.44 × 105 kg.
Physics
1 answer:
Illusion [34]3 years ago
7 0

Answer:

A) 27209506.5 N

B) 2393640 N

The force on the underwater vehicle is about 11.37 times the weight of the jetliner for comparison.

Explanation:

Force du to depth of water is

F = pghA

P = density of salt water = 1025 kg/m3

g = acceleration due to gravity 9.81 m/s2

h = depth of water 11000 m

A = area pressure acts

Area = ¶r^2 = 3.142 x 0.280^2 = 0.246 m^2

Therefore

F = 1025 x 9.81 x 11000 x 0.246

= 27209506.5 N

Weight of a jetliner with mass 2.44 × 10^5 kg is,

2.44×10^5 x 9.81 = 2393640 N

The force on the underwater vehicle is about 11.37 times the weight of the jetliner for comparison.

You might be interested in
A positively charged particle of mass 7.2 x 10-8 kg is traveling due east with a speed of 88 m/s and enters a 0.6-T uniform magn
Marianna [84]

Answer:

q = 8.57 10⁻⁵ mC

Explanation:

For this exercise let's use Newton's second law

         F = ma

where force is magnetic force

        F = q v x B

the bold are vectors, if we write the module of this expression we have

         F = qv B sin θ

as the particle moves perpendicular to the field, the angle is θ= 90º

        F = q vB

the acceleration of the particle is centripetal

        a = v² / r

we substitute

        qvB = m v² / r

         qBr = m v

          q =\frac{m\  v}{B\  r}

The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use

          v = d / t

the distance is ¼ of the circle,

          d = \frac{1}{4} \  2\pi  r

           d =\frac{\pi }{2r}

we substitute

           v =  \frac{\pi  r}{2t}

           r = \frac{2 \ t  \ v}{\pi }

           

let's calculate

           r =\frac{2 \ 2.2  \ 10^{-3} \ 88}{\pi } 2 2.2 10-3 88 /πpi

           r = 123.25 m

         

let's substitute the values

           q = \frac{ 7.2 \ 10^{-8} \ 88}{ 0.6 \ 123.25}7.2 10-8 88 / 0.6 123.25

            q = 8.57 10⁻⁸ C

Let's reduce to mC

           q = 8.57 10⁻⁸ C (10³ mC / 1C)

           q = 8.57 10⁻⁵ mC

4 0
2 years ago
Help me please, i need it fast
s2008m [1.1K]

Answer:

2)  C.  (x - 3)² + (y + 2)² = 25

5)   x² +  y² - 8x - 16y + 54 = 0

6)   x² + y²  - 10x - 12y + 36  = 0

Explanation:

2)

center of circle = 3, -2

                            x1, y1

end point of circle = 7, 1

                                 x2, y2

 

the equation of a circle is Pythagorean theorem

x² + y² = r²    (where r is the radius of a circle)

distance between points  

(x2 - x1)² + (y2 - y1)² = r²

(7 - 3)² + (1 - (-2))² = r²

r² = 25

therefore the equation to the circle is

(x - 3)² + (y + 2)² = 25

=========================================

5)

write the general form of a circle with the center (4,8)

and containing the point (-1, 7)

distance between points  

(x2 - x1)² + (y2 - y1)² = r²

(-1 - 4)² + (7 - 8)² = r²

r² = 26

(x - 4)² + (y - 8)² = 26

(x - 4)(x - 4) +  (y - 8)(y - 8) = 26

x² - 8x + 16 + y² - 16y + 64 -26 = 0

x² +  y² - 8x - 16y + 54 = 0

=========================================

6)

find the general form of a circle with center (5,6)

and tangent to the y-axis.

           

center (5,6)

           h, k

radius = r²

r = 5

(x - h)² + (y - k)² = r²

(x - r)² + (y - k)² = r²

(x - 5)(x - 5) + (y - 6)(y - 6) = r²

x² - 10x + 25 + y² - 12y + 36 = 25

x² + y²  - 10x - 12y + 36  = 0

=========================================

8 0
3 years ago
Occupants in a single space shuttle in orbit feel weightless. describe a scheme whereby occupants in a pair of shuttles (or even
agasfer [191]
The   scheme  whereby occupants  in  a  pair  of  shuttles is  as  follows
use  a  strong  cable  with  large  weight  on  the  end
Then  use  the  orbital  naneuvering   system(OMS)  to   set  the   whole  work  as  spinning   about   their  common  center of  gravity.
8 0
3 years ago
Does air resistence decrease with speed
dybincka [34]

Answer:

yes

Explanation:

because when you slow down, the resistance slows with the speed.

3 0
3 years ago
Read 2 more answers
Which change in an object would increase the force needed to move the object​
creativ13 [48]

Answer:

force is the answer because force is pushing the item

6 0
3 years ago
Other questions:
  • A spider of mass mm is swinging back and forth at the end of a strand of silk of length LL. During the spider's swing the strand
    12·1 answer
  • Which of the following statements is not true regarding atmospheric pressure?
    5·2 answers
  • How do u convert 7.68 cal/sec to kcal/min
    13·2 answers
  • A box with an open top has vertical sides, a square bottom, and a volume of 32 cubic meters. if the box has the least possible s
    6·1 answer
  • A particle moves along a circle with radius R, so that the tangential component of its acceleration is constant. At t = 0 the ve
    7·1 answer
  • Why can the Hubble space telescope make very detailed images in visible light
    5·1 answer
  • A man throws a ball vertically upward with an initial speed of 20m/s. What is the maximum height reached by the ball and how lon
    11·1 answer
  • HELPP!!!! URGENT!!!!
    11·1 answer
  • In a longitudinal wave, amplitude can be measured
    11·1 answer
  • A turtle starts at a velocity of 2 m/s and accelerates at a rate of 3 m/s2. How long will it take the turtle to reach a final ve
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!