Answer:
The probability of 3 students having blood type A is 1.23 , having blood type B is 0.3 and having blood type AB is 0.12
Step-by-step explanation:
Multiple the total selected nuber with the types .
Answer:
what is this
Step-by-step explanation:
Answer:
you use the mean method. and then round.
Answer:
P( sum is prime )= 73/216
Step-by-step explanation:
The minimum value of the sum will be 3 and maximum value will be 18. So the prime numbers in this range are 3 , 5, 7, 11, 13, 17.
P(sum=3)=1/216, P(sum=5)=6/216, P(sum=7)=15/216, P(sum=11)=27/216, P(sum=13)=21/216, P(sum=17)=3/216.
The final probability will be sum of the above given probabilities.
Hence P( sum is prime )= 73/216