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3 years ago

10

Find the length asap

2 answers:

IceJOKER [234]3 years ago

8 0

Answer:

11.62468045 or 11.6 to 1 decimal place

Step-by-step explanation:

→ We need to utilise trigonometry. The first step would be to list out the formula triangles

Tan = Opposite ÷ Adjacent

Sin = Opposite ÷ Hypotenuse

Cos = Adjacent ÷ Hypotenuse

→ Now we need to know which triangle to use, we do that by identifying the side or length we are not given in the triangle and then finding a formula without the name of the given side. First let's identify all the sides.

Opposite = AC = 16

Adjacent = BC = We need to find this out

Hypotenuse = AB = No given value

→ Now we look for a formula with hypotenuse

Tan = Opposite ÷ Adjacent

→ The (Tan = Opposite ÷ Adjacent) is the formula we are going to be using. Since we want to find out the adjacent, we have to rearrange to get adjacent as the subject

Adjacent = Opposite ÷ Tan

→ Now we identify the Opposite and the Tan

Opposite = 16

Tan = 54°

Side note ⇒ Sin, cos and tan will always be the angles

→ Substitute in the values in the formula

Adjacent = Opposite ÷ Tan ⇔ Adjacent = 16 ÷ Tan (54) ⇔ Adjacent = 11.6

→ The adjacent is 11.6 to 1 decimal place

Alla [95]3 years ago

6 0

Answer:

$\boxed{BC = 11.62}$

Step-by-step explanation:

Tan 54 = $\frac{opposite}{adjacent}$

Where opposite = 16, Adjacent = BC

1.376 = $\frac{16}{BC}$

BC = 16/1.376

BC = 11.62

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3 years ago

Read 2 more answers

ANSWER FAST ITS URGENT

Vlad1618 [11]

Answer:

9) 6.3 units

11) n=6√2 and m=12,

10) m=6√3, n=6

12) 330.6 ft

Step-by-step explanation:

1) The Pythagoras Theorem says that, the square of the hypotenuse is the sum of the squares of the two shorter legs.

Let the missing side, which is the hypotenuse be x.

Then

${x}^{2} = {2}^{2} + {6}^{2}$

${x}^{2} = 4 + 36$

${x}^{2} = 40$

$x = \sqrt{40}$

$x = 6.3$

The missing side is 6.3 units to the nearest tenth.

2) This is an isosceles right triangle.

This implies that, the two legs are equal.

$n = 6 \sqrt{2}$

The hypotenuse can be found using Pythagoras Theorem.

${m}^{2} = {(6 \sqrt{2} )}^{2} + {(6 \sqrt{2} )}^{2}$

${m}^{2} = 36(4)$

$m = \sqrt{36 \times 4} = 6 \times 2 = 12$

3) The side lengths of 30°-60°-90° are in the ratio, 2x,x√3,x

From the diagram, the hypotenuse is 12, therefore the other two legs are

$n = \frac{1}{2} (12) = 6$

and

$m = 6 \sqrt{3}$

4) The height of the monument is 115 feet, the hypotenuse is 350.

By Pythagoras Theorem,

${x}^{2} + {115}^{2} = {350}^{2}$

${x}^{2} = {350}^{2} - {115}^{2}$

${x}^{2} = 109275$

$x = \sqrt{109275} = 330.6 ft$

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4 years ago