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Alexxx [7]
2 years ago
5

A cube has a height of 8 cm and a mass of 457 g. What is its density?

Chemistry
1 answer:
ZanzabumX [31]2 years ago
3 0

Answer:

the answer is b,  0.89

Explanation:

A cube has a height of 8 cm and a mass of 457 g. What is its density?

a. 233,984 g/cm

b.  0.89g/cm3

c. 1.12 g/cm3

Density = mass/volume

the volume of the cube is 8X8X8=512cm3

the mass is 457 gm

the density is 457/512 = 0.889 gm/cm3

the answer is b, 0.89

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3. If 175 grams of nitrogen reacted with hydrogen to make hydrogen, how much ammonia would be needed?
zmey [24]

Answer:

37.5 g of H₂

Explanation:

N₂ (28g) + 3H₂ (6g) => 2NH₃ (34g)

Every 28g of N₂ needs 6g of H₂

=> Every 7g of N₂ needs 1.5g of H₂

=> 175g of N₂ needs 1.5 x 25 g of H₂

=> 37.5 g of H₂

7 0
2 years ago
The vapor pressure of water at 45oC is 71.88 mmHg. What is the vapor pressure of a sugar (C12H22O11) solution made by dissolving
Tju [1.3M]

Answer:

69.79 mmHg is the pressure for the solution

Explanation:

Formula for vapor pressure lowering:

Vapor pressure of pure solvent(P°) - Vapor pressure of solution (P') = P° . Xm

Xm → Molar fraction of solute (moles of solute / Total moles)

Total moles = Moles of solute + Moles of solvent

Let's determine the moles:

50.36 g . 1mol/342 g = 0.147 moles of sugar

88.69 g. 1mol/ 18g = 4.93 moles of water

Total moles = 0.147 + 4.93 = 5.077 moles

Xm = 0.147 / 5.077 = 0.0289

If we replace data given in the formula:

71.88 mHg - P' = 71.88 mmHg . 0.0289 . 0.0289

P' = - (71.88 mmHg . 0.0289 - 71.88 mmHg)

P' = 69.79 mmHg

5 0
3 years ago
Copper (II) sulfate pentahydrate may be heated to drive off the water of hydration. If 5 g of water are produced, what was the o
____ [38]

Answer:

13.9g of CuSO4•5H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CuSO4•5H2O → CuSO4 + 5H2O

Next, we shall determine the mass of CuSO4•5H2O heated and the mass of H2O produced from the balanced equation.

This is illustrated below

Molar mass of CuSO4• 5H2O = 63.5 + 32 + (16x4) + 5(2x1 + 16)

= 63.5 + 32 + 64 + 5(18) = 249.5g/mol

Mass of CuSO4•5H2O from the balanced equation = 1 x 249.5 = 249.5g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 5 x 18 = 90g

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Now, we can determine the mass of CuSO4•5H2O needed to produce 5g of H2O. This can be achieved as shown below:

From the balanced equation above,

249.5g of CuSO4•5H2O produced 90g of H2O.

Therefore, Xg of CuSO4•5H2O will produce 5g of H2O i.e

Xg of CuSO4•5H2O = (249.5 x 5)/90

Xg of CuSO4•5H2O = 13.9g

Therefore, 13.9g of CuSO4•5H2O is needed to produce 5g of H2O.

6 0
3 years ago
HELP WITH FINAL CHEM
atroni [7]

Answer:

idvd has a very high performance and a lot more than just the right side to get it all out

3 0
2 years ago
Sodium electron configuration
Helen [10]

Answer:  [Ne] 3s¹ sodium electron configuration

8 0
3 years ago
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