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Alexxx [7]
2 years ago
5

A cube has a height of 8 cm and a mass of 457 g. What is its density?

Chemistry
1 answer:
ZanzabumX [31]2 years ago
3 0

Answer:

the answer is b,  0.89

Explanation:

A cube has a height of 8 cm and a mass of 457 g. What is its density?

a. 233,984 g/cm

b.  0.89g/cm3

c. 1.12 g/cm3

Density = mass/volume

the volume of the cube is 8X8X8=512cm3

the mass is 457 gm

the density is 457/512 = 0.889 gm/cm3

the answer is b, 0.89

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andrey2020 [161]

Answer:

to increase the surface area

Explanation:

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3 years ago
What is the rule for elements with two<br> letters in the symbol?
Mumz [18]

Answer:

In these two-letter symbols, the first letter is always capitalized and the second is always lowercased.

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since the number of atoms in a substance is so large, a unit to count them was created. This unit is the number of atoms in 12 g
ASHA 777 [7]

Answer:

The mole was previously defined as the number of atoms determined experimentally to be found in 12 grams of carbon-12. The number of units in a mole also bears the name Avogadro's number, or Avogadro's constant, in honour of the Italian physicist Amedeo Avogadro.

Explanation:

I'm not entirely sure if i'm right but I hope this helps.

5 0
3 years ago
If you have 5.00 x 10^24 molecules of water how many moles of water would you<br> have?
shepuryov [24]

Answer:

8.31moles of H2O

Explanation:

Avogadro's hypothesis gives us an excellent understanding that 1mole of any substance contains 6.02x10^23 molecules. This means that 1mole H2O also contains 6.02x10^23 molecules.

Now, if 1 mole of H2O contains 6.02x10^23 molecules

Therefore, Xmol of H2O will contain 5.00x10^24 molecules i.e

Xmol of H2O = (5.00x10^24)/6.02x10^23 = 8.31moles of H2O

3 0
3 years ago
How many grams of CO2 are produced by the combustion of 289 g of a mixture that is 28.6% CH4 and 71.4% C3H8 by mass?
serg [7]

845 grams of CO2 are produced by the combustion of 289 g of a mixture that is 28.6% CH4 and 71.4% C3H8 by mass.

Explanation:

The mixture of methane and propane is butane with molecular formula

C4H12

on combustion the balanced reaction is:

C4H12 + 7 O2 ⇒   4CO2  + 6  H20

Molar mass of butane = 60.13 grams/mole, mass of C4H12 = 289 grams

number of moles of C2H12 is calculated by using the formula:

n = \frac{mass}{molar mass of 1 mole}

putting the values to know the moles of C4H12:

n = \frac{289}{60.13}

n = 4.8 moles of C4H12

from the balanced equation:

1 mole of C4H12 undergoes combustion to form 4 moles of CO2

thus, 4.8 moles when undergoes combustion will form x moles of CO2

\frac{4}{1}= \frac{x}{4.8}

X = 4 X 4.8

x = 19.2 moles of CO2 is formed.

to convert mole into mass, formula used:

mass = number of moles x atomic mass

         = 19.2 x 44.01

          = 844.99 grams of CO2 is formed.

3 0
4 years ago
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