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scZoUnD [109]
3 years ago
10

Compare the forces if the light truck is standing still when the car hits it. 1. The car exerts a greater amount of force on the

truck than the truck exerts on the car. 2. The truck exerts a greater amount of force on the car than the car exerts on the truck. 3. The truck exerts the same amount of force on the car as the car exerts on the truck. 4. None of the answers correctly describes the situation. 5. Neither exerts a force on the other; the
Physics
1 answer:
denis23 [38]3 years ago
5 0

Answer:

Only 3 is true: The truck exerts the same amount of force on the car as the car exerts on the truck.

Explanation:

Compare the forces if the light truck is standing still when the car hits it.

1. The car exerts a greater amount of force on the truck than the truck exerts on the car. FALSE. This violates Newton 3rd Law of Action-Reaction.

2. The truck exerts a greater amount of force on the car than the car exerts on the truck. FALSE. This violates Newton 3rd Law of Action-Reaction.

3. The truck exerts the same amount of force on the car as the car exerts on the truck. TRUE. This is Newton 3rd Law of Action-Reaction. When there is a contact between objects, both exert on the other an equal and opposite force.

4. None of the answers correctly describes the situation. FALSE. 4 is true.

5. Neither exerts a force on the other. FALSE. If the car hits it then forces must come into play.

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Answer:240 meters

Explanation:60×4

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3 years ago
What is the kinetic energy of an object that has a mass of 50.0kg and a velocity of 18 m/s?
Rom4ik [11]
<h2>Answer </h2>

The kinetic energy is 8100 J.

<u>Explanation</u>

Mass is 50.0kg and velocity is 18 m/s, the kinetic energy is:

As we know the formula of kinetic energy which is K.E = ½ ( mv ^ 2 ),

mass = m = 50.0kg

velocity = v = 18 m / s,

by putting values in the formula,

K.E = ½ ( mv ^ 2 ),

K.E = ½ ( 50kg ) . ( 18 m / s ) ^ 2

K.E = ½ ( 50kg ) . ( 324 ),

=> K.E = 1/2 ( 16200 ),

=> K.E = 16200 / 2,

=> K.E = 8100J.

Hence, the kinetic energy ( K.E ) is 8100 joule ( J ).  

7 0
3 years ago
A pipe of length 6.8 m is closed at one end and sustains a standing wave at its second overtone. determine the distance between
r-ruslan [8.4K]
For a pipe closed at one end, the second overtone is the 3rd natural frequency as shown in the diagram.

For the fundamental frequency,
λ = 4L
where
λ = wavelength
L = the length of the tube

For the second overtone (3rd frequency)
λ = (4/3)L

Because L = 6.8 m, therefore
λ = (4/3)*(6.8 m) = 9.0667 m

The distance between a node and an adjacent antinode is λ/2, which is
9.0667/2 = 4.533 m

Answer: 4.5 m

8 0
3 years ago
If a seismic wave has a period of 0.0202s, find the frequency of the wave.
maw [93]

Answer:

49.5 Hz.

Explanation:

From the question given above, the following data were obtained:

Period (T) = 0.0202 s

Frequency (f) =?

The frequency and period of a wave are related according to the following equation:

Frequency (f) = 1 / period (T)

f = 1/T

With the above formula, we can obtain the frequency of the wave as follow:

Period (T) = 0.0202 s

Frequency (f) =?

f = 1/T

f = 1/0.0202

f = 49.5 Hz

Therefore the frequency of the wave is 49.5 Hz.

7 0
3 years ago
How does the north pole of a magnet respond to the poles of other magnets?
tensa zangetsu [6.8K]

Answer:

Explanation:

A magnet has a magnetic field around it which originates at the north pole and enters through the south pole.

In a magnet, like poles will repel each other and unlike poles will attract.

  • The north pole of one magnet will repel another north pole of another magnet.
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8 0
3 years ago
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