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scZoUnD [109]
3 years ago
10

Compare the forces if the light truck is standing still when the car hits it. 1. The car exerts a greater amount of force on the

truck than the truck exerts on the car. 2. The truck exerts a greater amount of force on the car than the car exerts on the truck. 3. The truck exerts the same amount of force on the car as the car exerts on the truck. 4. None of the answers correctly describes the situation. 5. Neither exerts a force on the other; the
Physics
1 answer:
denis23 [38]3 years ago
5 0

Answer:

Only 3 is true: The truck exerts the same amount of force on the car as the car exerts on the truck.

Explanation:

Compare the forces if the light truck is standing still when the car hits it.

1. The car exerts a greater amount of force on the truck than the truck exerts on the car. FALSE. This violates Newton 3rd Law of Action-Reaction.

2. The truck exerts a greater amount of force on the car than the car exerts on the truck. FALSE. This violates Newton 3rd Law of Action-Reaction.

3. The truck exerts the same amount of force on the car as the car exerts on the truck. TRUE. This is Newton 3rd Law of Action-Reaction. When there is a contact between objects, both exert on the other an equal and opposite force.

4. None of the answers correctly describes the situation. FALSE. 4 is true.

5. Neither exerts a force on the other. FALSE. If the car hits it then forces must come into play.

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An artist wants to create a metal sculpture using a mold so that his artwork can be readily mass produced. He wants his sculptur
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In which medium does light travel faster: one with a critical angle of 27.0° or one with a critical angle of 32.0°? Explain. (Fo
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Answer:

Among those two medium, light would travel faster in the one with a reflection angle of 32^{\circ} (when light enters from the air.)

Explanation:

Let v_{1} denote the speed of light in the first medium. Let v_{\text{air}} denote the speed of light in the air. Assume that the light entered the boundary at an angle of \theta_{1} to the normal and exited with an angle of \theta_{\text{air}}. By Snell's Law, the sine of \theta_{1}\! and \theta_{\text{air}}\! would be proportional to the speed of light in the corresponding medium. In other words:

\displaystyle \frac{v_{1}}{v_{\text{air}}} = \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})}.

When light enters a boundary at the critical angle \theta_{c}, total internal reflection would happen. It would appear as if the angle of refraction is now 90^{\circ}. (in this case, \theta_{\text{air}} = 90^{\circ}.)

Substitute this value into the Snell's Law equation:

\begin{aligned}\frac{v_{1}}{v_{\text{air}}} &= \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})} \\ &= \frac{\sin(\theta_{c})}{\sin(90^{\circ})} \\ &= \sin(\theta_{c})\end{aligned}.

Rearrange to obtain an expression for the speed of light in the first medium:

v_{1} = v_{\text{air}} \cdot \sin(\theta_{1}).

The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.

For 0 < \theta < 90^{\circ}, \sin(\theta) is monotonically increasing with respect to \theta. In other words, for \!\theta in that range, the value of \sin(\theta)\! increases as the value of \theta\! increases.

Therefore, compared to the medium in this question with \theta_{c} = 27^{\circ}, the medium with the larger critical angle \theta_{c} = 32^{\circ} would have a larger \sin(\theta_{c}). such that light would travel faster in that medium.

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