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3 years ago

The atomic number of an atom is the number of ____.

Physics

2 answers:

Anestetic [448]3 years ago

6 0

It is for sure protons i just took the test.

NISA [10]3 years ago

3 0

D protons

k12 student here

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The energy consumed by a home during a month is 90 kWh, how many Joules are we talking about? a good explanation please is for t

andreev551 [17]

Answer:

3.24×10⁸ J, or 324 MJ

Explanation:

"kWh" is a kilowatt-hour. It's the energy used by 1 kilowatt of power after one hour.

A kilowatt is a kilojoule per second.

90 kWh

= 90 kW × 1 hr

= 90 kJ/s × 1 hr

= 90 kJ/s × 3600 s

= 324,000 kJ

= 324,000,000 J

The energy is 3.24×10⁸ J, or 324 megajoules.

3 0

2 years ago

Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears a maximum sound intensity when sp

grandymaker [24]

Answer:

frequency of the sound = f = 1,030.3 Hz

phase difference = Φ = 229.09°

Explanation:

Step 1: Given data:

Xini = 0.540m

Xfin = 0.870m

v = 340m/s

Step 2: frequency of the sound (f)

f = v / λ

λ = Xfin - Xini = 0.870 - 0.540 = 0.33

f = 340 / 0.33

f = 1,030.3 Hz

Step 3: phase difference

phase difference = Φ

Φ = (2π/λ)*(Xini - λ) = (2π/0.33)* (0.540-0.33) = 19.04*0.21 = 3.9984

Φ = 3.9984 rad * (360°/2π rad)

Φ = 229.09°

Hope this helps!

5 0

2 years ago

A circular coil of 185 turns has a radius of 1.60 cm. (a) Calculate the current that results in a magnetic dipole moment of magn

s344n2d4d5 [400]

Answer:

(a) the current in the coil is 12.03 A

(b) the maximum magnitude of the torque is 0.0854 N.m

Explanation:

Given;

number of turns, N = 185

radius of the coil, r = 1.6 cm = 0.016 m

magnetic dipole moment, μ = 1.79 A·m²

Part (a) current in the coil

μ = NIA

Where;

I is the current in the coil

A is the of the coil = πr² = π(0.016)² = 0.000804 m²

I = μ / (NA)

I = 1.79 / (185 x 0.000804)

I = 1.79 / 0.14874

I = 12.03 A

Part (b) the maximum magnitude of the torque

τ = μB

Where;

τ is the maximum magnitude of the torque

B is the magnetic field strength = 47.7 mT

τ = 1.79 x 0.0477 = 0.0854 N.m

4 0

3 years ago

Read 2 more answers

We can model the motion of a bumblebee's wing as simple harmonic motion. A bee beats its wings 250 times per second, and the win

zlopas [31]

Answer:

The amplitude of the wing tip's motion is 1.6 mm.

Explanation:

Given that,

Beat = 250 /s

Speed = 2.5 m/s

We need to calculate the amplitude of the wing tip's motion

Using the equation for the maximum velocity

$v_{max}=2\pi f A$

$A=\dfrac{v}{2\pi f}$

Where,

v = speed

f = frequency

A = amplitude

Put the value into the formula

$A=\dfrac{2.5}{2\pi\times250}$

$A=0.00159 = 1.59\times10^{-3}\ m$

$A=1.6\ mm$

Hence, The amplitude of the wing tip's motion is 1.6 mm.

3 0

3 years ago

Read 2 more answers

By how many decibels do you reduce the sound intensity level due to a source of sound if you triple your distance from it? assum

sweet-ann [11.9K]

New sound intensity level after the move is

      10 log (1/3²)

   = -20 log (3)

   = -20 (0.4771) =   9.54 dB LOWER than before the move.

4 0

2 years ago