The initial force of the throw overcomes gravity quite easily. Then, gravity begins to bring it back down to earth, making a curved path.
Answer:
80.6 mV
Explanation:
Parameters given:
Number of turns, N = 115
Radius of coil, r = 2.71 cm = 0.0271m
Time taken, t = 0.133s
Initial magnetic field, Bin = 50.1 mT = 0.0501 T
Final magnetic field, Bfin = 90.5 mT = 0.0905 T
Induces EMF is given as:
EMF = [(Bfin - Bin) * N * A] / t
EMF = [(0.0905 - 0.0501) * 115 * pi * 0.0271²] / 0.133
EMF = (0.0404 * 115 * 3.142 * 0.0007344) / 0.133
EMF = 0.0806 V = 80.6 mV
<span>Large intestine, small intestine, rectum is the correct order.</span>
Answer:
Explanation:
a ) The direction of angular velocity vector of second hand will be along the line going into the plane of dial perpendicular to it.
b ) If the angular acceleration of a rigid body is zero, the angular velocity will remain constant.
c ) If another planet the same size as Earth were put into orbit around the Sun along with Earth the moment of inertia of the system will increase because the mass of the system increases. Moment of inertia depends upon mass and its distribution around the axis.
d ) Increasing the number of blades on a propeller increases the moment of inertia , because both mass and mass distribution around axis of rotation increases.
e ) It is not possible that a body has the same moment of inertia for all possible axes because a body can not remain symmetrical about all axes possible. Sphere has same moment of inertia about all axes passing through its centre.
f ) To maximize the moment of inertia of a flywheel while minimizing its weight, the shape and distribution of mass should be such that maximum mass of the body may be situated at far end of the body from axis of rotation . So flywheel must have thick outer boundaries and this should be
attached with axis with the help of thin rods .
g ) When the body is rotating at the same place , its translational kinetic energy is zero but its rotational energy can be increased
at the same place.
Answer:
ω = 3.61 rad/sec
Explanation:
Firstly, we should know that the bug will not slip if friction can provide sufficient opposing force.
μmg = mv^2/r = mω^2r
Thus;
μg = ω^2r
ω^2 = μg/r
ω = √(μg/r)
ω = √(0.321 * 9.8)/0.241
ω = √(13.05)
= 3.61 rad/sec
