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zvonat [6]
4 years ago
14

If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct

ure The central X atom is single bonded to two Y atoms, which are 180 degrees apart. The X atom has two lone pairs. could be abbreviated as XY2Z2. Classify each molecule according to its shape.Molecular Geometries: linearbent 120bent 109trigonal pyramidalT-shapedsee sawsquare planarsquare pyramidalPossiblities:XY4Z2XY5ZXY2ZXY2Z3XY4ZXY2Z2XY3Z2XY3Z
Chemistry
1 answer:
Snowcat [4.5K]4 years ago
8 0

Answer:

XY4Z2 ----- square planar

XY5Z ------- square pyramidal

XY2Z----- bent < 120°

XY2Z3 ----- Linear

XY4Z ---- see saw

XY2Z2 ----- bent <109°

XY3Z2 ----- T shaped

XY3Z ----- Trigonal pyramidal

Explanation:

The valence shell electron pair repulsion theory ( VSEPR) gives the description of molecular geometry based on the relative number of electron pairs present in the molecule.

However, electron pairs repel each other, the repulsion between two lone pairs is greater than the repulsion between a lone pair and a bond pair which is also greater than the repulsion between two lone pairs.

The presence of lone pairs distort the bond angle and molecular geometry from the expected geometry based on VSEPR theory. Hence, in the presence of lone pairs of electron, the observed molecular geometry may be different from that predicted on the basis of the VSEPR theory, the bond angles also differ slightly or widely depending on the number of lone pairs present.

All the molecules in the question possess lone pairs, the number of electron pairs do not correspond to the observed molecular shape or geometry due to lone pair repulsion. Usually, the molecular geometry deals more with the arrangement of bonded atoms in the molecule.

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En 1500 kg de aire hay 0.8 g de dióxido de carbono a cuantos ppm corresponde la muestra de co2
Alex Ar [27]

Translation:

In 1500 kg of air there are 0.8 carbon dioxide. How many ppm does the carbon dioxide sample correspond to?

Explanation:

Given parameters:

Mass of air = 1500kg

Mass of carbon dioxide= 0.8g

Unknown:

PPM of carbon dioxide in the sample = ?

SOLUTION :

The parts per million ppm is used to express dilute concentration of solutes. It simple means out of a million.

To express the answer in ppm, first convert into uniform units:

  1500kg to g = ?

             1kg = 1000g

             1500kg = (1500 x 1000)g = 1500000g

To express as part per million:

\frac{mass of carbon dioxide}{mass of air} x 1000000

         \frac{0.8}{1500000} x 1000000 = 0.533ppm

Learn more:

Parts per million brainly.com/question/2854033

#learnwithBrainly

4 0
3 years ago
Ethanol is an example of an ____________ (carboxyl/alcohol).
Leno4ka [110]

it cannot be  carboxyl..... ethanol cannot be an example of carboxyl

and ethanol is an alcohol ..... so therefore the answer is alcohol

5 0
4 years ago
Periodic table the first row of elements fits in the period blank after the element blank the second row of elements fits in per
Bezzdna [24]

Answer:

The first row fits in period 2

The second row fits in period 3

Explanation:

Elements arranged vertically in the periodic table in groups that share similar chemical properties.

Elements are also organized horizontally in rows or periods

The length of each period is determined by the number of electrons that can occupy the sublevels being filled in that period.

7 0
3 years ago
A(n) ________________ is a structure or behaviors in organisms that help them survive in their environment.
Lapatulllka [165]

Answer:

Adaptations

Explanation:

Adaptation is simply defined as a specific characteristics of an animal or plant which can be a body part, body covering, or behavior that helps an animal or plant survive in its environment.

The common types of Adaptations includes Physical adaptation which entails a change to a part of the body and Behavioral adaptation which is simply what an animal does in response to an external stimulus.

Examples of Adaptation includes Hibernation, Camouflage, Mimicry, Whiskers, Beaks and others. In plants, seed colour, hard endocarp, secretions e. t. c helps them survive in their environment.

6 0
3 years ago
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e
notsponge [240]

<u>Answer:</u> The concentration of Sn^{2+} in the cell is 9.0\times 10^{-3}M

<u>Explanation:</u>

We are given:

<u>Oxidation half reaction:</u>  Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-   E^o_{Zn^{2+}/Zn}=-0.76V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)   E^o_{Sn^{2+}/Sn}=-0.136V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Here, tin will undergo reduction reaction and will get reduced.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=-0.136-(-0.76)=0.624V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Mn^{2+}]}{[Cu^{2+}]}

where,

E_{cell} = electrode potential of the cell = 0.660 V

E^o_{cell} = standard electrode potential of the cell = +0.624 V

n = number of electrons exchanged = 2

[Zn^{2+}]=2.5\times 10^{-3}M

[Sn^{2+}] = ?

Putting values in above equation, we get:

0.660=0.624-\frac{0.059}{2}\times \log(\frac{2.5\times 10^{-3}}{[Sn^{2+}})

[Sn^{2+}]=9.0\times 10^{-3}M

Hence, the concentration of Sn^{2+} ions is 9.0\times 10^{-3}M

3 0
3 years ago
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