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zvonat [6]
3 years ago
14

If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct

ure The central X atom is single bonded to two Y atoms, which are 180 degrees apart. The X atom has two lone pairs. could be abbreviated as XY2Z2. Classify each molecule according to its shape.Molecular Geometries: linearbent 120bent 109trigonal pyramidalT-shapedsee sawsquare planarsquare pyramidalPossiblities:XY4Z2XY5ZXY2ZXY2Z3XY4ZXY2Z2XY3Z2XY3Z
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

XY4Z2 ----- square planar

XY5Z ------- square pyramidal

XY2Z----- bent < 120°

XY2Z3 ----- Linear

XY4Z ---- see saw

XY2Z2 ----- bent <109°

XY3Z2 ----- T shaped

XY3Z ----- Trigonal pyramidal

Explanation:

The valence shell electron pair repulsion theory ( VSEPR) gives the description of molecular geometry based on the relative number of electron pairs present in the molecule.

However, electron pairs repel each other, the repulsion between two lone pairs is greater than the repulsion between a lone pair and a bond pair which is also greater than the repulsion between two lone pairs.

The presence of lone pairs distort the bond angle and molecular geometry from the expected geometry based on VSEPR theory. Hence, in the presence of lone pairs of electron, the observed molecular geometry may be different from that predicted on the basis of the VSEPR theory, the bond angles also differ slightly or widely depending on the number of lone pairs present.

All the molecules in the question possess lone pairs, the number of electron pairs do not correspond to the observed molecular shape or geometry due to lone pair repulsion. Usually, the molecular geometry deals more with the arrangement of bonded atoms in the molecule.

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A 25.0 mL sample of a saturated C a ( O H ) 2 solution is titrated with 0.029 M H C l , and the equivalence point is reached aft
Gnesinka [82]

Answer:

0.043 M

Explanation:

The reaction that takes place is:

  • Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

First we <u>calculate how many HCl moles reacted</u>, using the <em>given concentration and volume required to reach the equivalence point</em>:

  • 0.029 M HCl * 37.3 mL = 1.0817 mmol HCl = 1.0817 mmol H⁺

As 1 mol of H⁺ reacts with 1 mol of OH⁻, in the 25.0 mL of the Ca(OH)₂ sample there are 1.0817 mmoles of OH⁻.

With that in mind we can <u>calculate the hydroxide ion concentration in the original sample solution</u>, using <em>the calculated number of moles and given volume</em>:

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3 years ago
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3 years ago
What mass of aluminum is produced by the decomposition of 5.0 kg al2o3?
Nina [5.8K]
The  mass for  of aluminum that is produced  by  the decomposition  of  5.0 Kg Al2O3 is 2647 g or 2.647  Kg

          calculation
  Write  the equation for decomposition  of Al2O3

Al2O3 = 2Al  + 3 O2

find the  moles  of  Al2O3 =  mass/molar mass

convert  5 Kg  to g   = 5 x1000 = 5000 grams
molar mass of  Al2O3 =  27 x2 + 16 x3  = 102 g/mol

 moles =5000 g/  102 g/mol = 49.0196 moles

by use  of mole ratio between Al2O3 to  Al  which is 1:2  the moles of Al = 49.0196 x2 =98.0392  moles


mass of  Al = moles x molar  mass

= 98.0392 moles x  27g/mol = 2647  grams  or 2647/1000 = 2.647 Kg


7 0
3 years ago
Read 2 more answers
In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?
Bezzdna [24]
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Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH) 
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