The half-life of Plutonium−239, t1/2 is 2.41 × 10⁴<span> yrs
time taken to reach tolerable level = seven half-lives
= 7 x t1/2
= 7 x </span>2.41 × 10⁴ yrs
= 168700 yrs
= 1.687 x 10⁵ yrs
Hence, the period of time that <span>Plutonium-239 must be stored is </span>1.687 x 10⁵ years.
The mass would be the sum of the protons and neutrons. Your answer would be 218
Answer:
7.28 moles Ag°
Explanation:
Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°
Given 7.28 moles 7.28 moles
To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...
Limiting reactant determination:
Cu° + 2 AgNO₃ => Cu(NO₃)₂ + 2Ag°
Cu: 7.28 / 1 = 7.28
AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃
Solving Problem depends on AgNO₃; Cu will be in excess.
Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.
Answer:
0.00731 kg
Explanation:
Given that solution is a product of solute and solvent.
Hence, solution = solute * solvent
In this case, the solution is given as 0.950 grams = 0.00095 kilograms
solute is given as 130 grams = 0.13 kilograms
Hence to get the amount of solvent in kilograms, we have
Solution ÷ Solute => 0.00095 ÷ 0.13
= 0.0073076923
=> 0.00731 kilograms
<span>*The difference between malleability and ductility is that malleability is the ability to deform easily upon the application of a compressive force, and ductility is doing the same with tensile force.
</span>
