We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em> XeF₆</em>
Answer:
we count the number of the molecules on each side of the equation.
I think the answer is D (number 4)
<span>Presumably, any salt-to-water ratio would be low, if the water molecules are not removed from the solution, whatever it may be, as salt is typically a very small potion in saline water.</span>
An analogy is a comparison between two things
Example: banana is to yellow as red is to apple OR banana:yellow as red:apple
A metaphor is a figure of speech where a word or phrase is applied and it’s not literal.
Example: it’s raining cats and dogs. It’s not really raining literal cats and dogs. It’s just raining really hard.
