The solution is as follows:
K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106
The molar mass of isoborneol/borneol is 154.25 g/mol
Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol
Use the ICE approach
borneol → isoborneol
I 0.0972 0.0486
C -x +x
E 0.0972 - x 0.0486 + x
Total moles = 0.1458
Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P
0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832
Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
Answer:
Following are the solution to these question:
Explanation:
Calculating the mean:
Calculating the standardn:
Please find the correct equation in the attached file.
For point a:
For point b:
For point c:
It is calculated by using the slope value that is 
. The slope value is ambiguous.
<span>The smallest unit of a compound is called a molecule. The correct option among all the options that are given in the question is the second option or the penultimate option or option "B". The other choices are incorrrect and can be negated. I hope that this is the answer that has actually come to your desired help.</span>
You can make 10 because that is the most N2 you have. The first one that runs out limits further molecules to be made
I think it would be solubility but I’m not sure
