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ankoles [38]
2 years ago
13

ACFrOgDjZVP5d1mO2l6HAtPZQNnbFRq674g04E7uZadqJMPc4VbhdTIEDCWBeh3xfw9BrKkfHHEN4nxe9NVglsb9N8D49CjxvxHYw3L93m4wO6SY5SwKQYMk-2zzHtGz

erun1Uh9k-mpxFw9D3I1.pdf
Chemistry
1 answer:
Dmitrij [34]2 years ago
5 0

Answer:

No hay resultados para ACFrOgDjZVP5d1mO2l6HAtPZQNnbFRq674g04E7uZadqJMPc4VbhdTIEDCWBeh3xfw9BrKkfHHEN4nxe9NVglsb9N8D49CjxvxHYw3L93m4wO6SY5SwKQYMk-2zzHtGzerun1Uh9k-mpxFw9D3I1.pdf

Explanation:

hablemos por g mail

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Which element is a liquid at 1000 k <br><br> 1.Ag<br> 2.Al<br> 3.Ca<br> 4.Ni
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From the amount of NaOH added at the 1st equivalence point, calculate the original molarity of the acid. Carry out the same calc
gizmo_the_mogwai [7]

Answer:

Molarity of acid, Ca = Cb*Vb*A/Va*B

Explanation:

Using H2SO4 as acid, the reaction is as follow:

2NaOH  +  H2SO4 ⇒ Na2SO4  +  2H2O

Volume of acid = Va; Volume of base = Vb, Molar concentration of  acid = Ca; Molar concentration of base = Cb; Molarity of acid = A and Molarity of base = B

Ca*Va/Cb*Vb =A/B

∴ Ca = Cb*Vb*A/Va*B

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