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Elena L [17]
2 years ago
12

What is the mass of 4.5 x 10^22 molecules of hydrogen peroxide H2O2

Chemistry
1 answer:
Oksana_A [137]2 years ago
5 0

Answer:

The answer is 2.54g

To find the mass we must first find the number of moles we use the Formula ;

N = n × L

where

N is the number of entities

n is the number of moles

L is the Avogadro's constant which is

6.023 × 10^23

n = N / L

N = 4.5 x 10^22 molecules

n = 4.5 x 10^22 / 6.023 × 10^23

n = 0.0747 moles

Molar mass = mass / number of moles

Molar mass of H2O2 = (2 × 1) + (16 × 2)

= 2 + 32

= 34g/mol

mass = molar mass × number of moles

= 34 × 0.0747

= 2.5398

= 2.54g

Hope this helps

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If you are given an ideal gas with pressure (p)259,392.00 pa and temperature (T)=200°c of 1 mole Argon gas in a volume 8.8dm3,ca
GuDViN [60]

Answer: R=4.82436 \frac{Pa. m^{3}}{mol. K}

Explanation:

The Ideal Gas equation is:  

P.V=n.R.T  (1)

Where:  

P is the pressure of the gas  

n the number of moles of gas  

R=8.3144598 \frac{Pa. m^{3}}{mol. K} is the gas constant  

T is the absolute temperature of the gas in Kelvin.

V is the volume

It is important to note that the behavior of a real gas is far from that of an ideal gas, taking into account that <u>an ideal gas is a single hypothetical gas</u>. However, under specific conditions of standard temperature and pressure (T=0\°C=273.15 K and P=1 atm=101,3 kPa) one mole of real gas (especially in noble gases such as Argon) will behave like an ideal gas and the constant R will be 8.3144598 \frac{Pa. m^{3}}{mol. K}.

However, in this case we are not working with standard temperature and pressure, therefore, even if we are working with Argon, the value of R will be far from the constant of the ideal gases.

Having this clarified, let's isolate R from (1):

R=\frac{PV}{nT}  (2)

Where:

P=259392 Pa

n=1 mole

T=200\°C=473.15 K is the absolute temperature of the gas in Kelvin.

V=8.8 dm^{3}=0.0088 m^{3}

R=\frac{(259392 Pa)(0.0088 m^{3})}{(1 mole)(473.15 K)}  (3)

Finally:

R=4.82436 \frac{Pa. m^{3}}{mol. K}  

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