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Usimov [2.4K]
3 years ago
11

How are science and technology related?

Chemistry
2 answers:
netineya [11]3 years ago
4 0
<span>C. Advances in science may lead to advances in technology and vice versa is the correct answer~</span>
aev [14]3 years ago
3 0
It's not A because technology is a branch of applied science. It's not B because again, technology is a branch of science, not the other way around. It's not D because they are related with one being a branch of another. Therefore, it has to be C because scientific advances do lead to technological advances.
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Is there a similarity between this investigation and the human body/diet? Explain.
Len [333]

Answer:

In a nutshell, diet refers to all the food that you consume through the day, on a regular basis. Nutrition, on the other hand, refers to the fuel that your body requires to function optimally and maintain good health. It refers to the right mix of nutrients.

Explanation:

3 0
2 years ago
Read 2 more answers
Which statement best demonstrates how data from a global positioning system (GPS) can be used to lessen the effects of a
dolphi86 [110]

Answer: here is your answer

Explanation: You are visiting your Grandmother and notice that she is eating a balanced diet, taking vitamins, getting the proper amount of sleep and is not overweight. Despite her healthy lifestyle, she appears run down and tired. You realize that it's due to her lack of physical activity. Write a convincing letter to your grandma explaining the benefits of participating in regular physical activity.

3 0
3 years ago
What is the vapor pressure of CS2CS2 in mmHgmmHg at 26.5 ∘C∘C? Carbon disulfide, CS2CS2, has PvapPvap = 100 mmHgmmHg at −−5.1 ∘C
Digiron [165]

Answer: 26.5 mm Hg

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at 26.5^oC = ?

P_2 = final pressure at -5.1^oC = 100 mm Hg

= enthalpy of vaporisation = 28.0 kJ/mol =28000 J/mol

R = gas constant = 8.314 J/mole.K

T_1= initial temperature = 26.5^oC=273+26.5=299.5K

T_2 = final temperature =-5.1^oC=273+(-5.1)=267.9K

Now put all the given values in this formula, we get

\log (\frac{P_1}{100})=\frac{28000}{2.303\times 8.314J/mole.K}[\frac{1}{299.5}-\frac{1}{267.9}]

\log  (\frac{P_1}{100})=-0.576

\frac{P_1}{100}=0.265

P_1=26.5mmHg

Thus the vapor pressure of CS_2CS_2 in mmHg at 26.5 ∘C is 26.5

7 0
3 years ago
The two sides of the equation should be
KonstantinChe [14]

Answer:

Hey mate.....

Explanation:

This is ur answer.....

---> Equal

hope it helps,

mark me as the brainliest,

Follow me......

8 0
3 years ago
Read 2 more answers
A. At STP, what is the volume of 708 mol of nitrogen gas? 708 mol = 708 mol X L B. A sample of hydrogen gas occupies 14.1 L at S
elena-14-01-66 [18.8K]

Answer:

A. 15859.2 L or 15900 L

B. 0.629 mol

Explanation:

At STP, one mole is equal to approximately 22.4 L

L or mL is volume, so you are attempting to solve for L or mL.

A.

708 mol x (22.4 L/1 mol) = 15859.2 L (w/ significant figures included - 15900 L)

B.

(14.1 L) x (1 mole/ 22.4 L) = 0.629 mol.

5 0
2 years ago
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