Answer:

Explanation:
We are asked to find the density of a brick. Density is a substance's mass per unit volume. The formula for calculating density is as follows.

The mass of the brick is 100 grams and the volume is 25 cubic centimeters.
Substitute the values into the formula.

Divide.

The density of the brick is <u>4 grams per cubic centimeter.</u>
Unstable isotopes occur when the strong force is unable to overcome the <span> <span>electrostatic force.</span></span><span>
There are no stable isotopes in the elements at the upper end of the periodic table, which clearly demonstrates the limit of the ability of the nuclear binding energy or the residual strong force, to overcome the electrostatic repulsion of all those protons in the nucleus.
</span>
Explanation:
The given balanced reaction is as follows.

It is given that mass of ammonium nitrate is 86.0 kg.
As 1 kg = 1000 g. So, 86.0 kg = 86000 g.
Hence, moles of
present will be as follows.
Moles of
= 
= 
= 1074.42 mol
Therefore, moles of
,
and
produced by 1074.42 mole of
will be as follows.
Moles of
= 
= 537.21 mol
Moles of
= 
= 1074.42 mol
Moles of
= 
= 2148.84 mol
Therefore, total number of moles will be as follows.
537.21 mol + 1074.42 mol + 2148.84 mol
= 3760.47 mol
According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.
PV = nRT
1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex] (as
= 307 + 273 = 580 K)
V = 179066.06 L
Thus, we can conclude that total volume of the gas is 179066.06 L.
Answer: 3 moles Na
Explanation: To find the number of moles of Na, divide the number of atoms of Na with the Avogadro's Number.
1.806x10²⁴ atoms Na x 1 mole Na / 6.022x10²³ atoms Na
= 2.99 or 3 moles Na
Answer:
1640 kJ are involved in the reaction
Explanation:
In the reaction:
B₂H₆(g) + 6Cl₂(g) → 2 BCl₃(g) + 6HCl(g)
<em>1 mol of B₂H₆(g) with 6 moles of Cl₂(g) produce 1396 kJ of energy.</em>
<em />
Now if 32.5g of B₂H₆(g) react with excess Cl₂(g), moles involved in reaction are:

If 1 mol produce 1396kJ of energy, 1.175 moles produce:

Thus, <em>1640 kJ are involved in the reaction</em>