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3 years ago

The function f(x) = (x - 4)(x - 2) is shown.

Mathematics

1 answer:

Alexxx [7]3 years ago

3 0

Answer:

All real numbers greater than or equal to -1

Step-by-step explanation:

f(x) = (x-3)^2 - 1 >= -1

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A company purchased a machine for $970,000. the machine has a useful life of 12 years and a residual value of $4,500. it is esti

harina [27]

Cost less salvage value = 970,000 - 4500 = 965,500
Capacity of machine = 1,000,000 units.
units consumed at the end of second year = 200,000 + 300,000 = 500,000 units.
Capacity remaining = 1,000,000 - 500,000 = 500,000 units
Book value at end of second year = (500,000/1,000,000)*965,500 + 4500
= $487,250

8 0

3 years ago

Jimmy is selling used books at a yard sale. A customer buys 9 books at a cost of $0.75 each and pays with a $20.00 bill. Jimmy m

yanalaym [24]

Answer:

$13.25

Step-by-step explanation:

hope this helps

5 0

3 years ago

Read 2 more answers

−5.5x + 0.46 = −3.94

aliina [53]

Answer:

x= 0.78 (rounded to the hundredth)

Step-by-step explanation:

-5.5x + 0.46 = -3.94

You need to isolate x so the easiest thing to do is subtract 0.46 and move it to the other side of the equal sign.

-5.5x= -3.84 - 0.46

-5.5x = -4.3

divide -5.5 to get x alone

x= -4.3/-5.5

x= 0.78

7 0

3 years ago

Which lists all the integer solutions of the equation |x| = 10?

kakasveta [241]

There is no list and no choices given.

The solutions of | x | = 10 are x = 10 and x = -10 .

All (both) solutions happen to be integers.
There are no other solutions.

5 0

3 years ago

Read 2 more answers

g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20

Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

$X\sim N(\mu = 50, \sigma =6)$

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0

3 years ago