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Tamiku [17]
3 years ago
7

The table below lists the properties of a metallic element. Shiny, Silver colored, Forms +1 and +2 ions, compound with sulfur is

bright red. Where on the periodic table would this element most likely be found?
Group 1
Group 2
Group 12
Group 13

Chemistry
2 answers:
LuckyWell [14K]3 years ago
8 0

Answer:

12

Explanation:

shtirl [24]3 years ago
5 0

Answer:

The correct option is;

Group 12

Explanation:

A metallic element that is shiny and silver colored that can exist in the +1 and +2 ionic states and  which forms a bright red compound with sulfur is mercury, Hg

The compound formed between mercury and silver is one of the earliest synthetic compound also known as vermilion and cinnabar. The bright red pigment of the HgS is used widely and is one of the most favorite pigment found in medieval European outstanding works of arts and in Chinese decorated wares made of lacquer as well as in mesoAmerica.

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The weights of all elements are always compared to oxygen.<br> True <br> False
kozerog [31]

Answer:

false

Explanation:

I'm pretty sure it's compared to carbon

8 0
3 years ago
Read 2 more answers
A mixture of helium and nitrogen gases, in a 7.03 L flask at 17 °C, contains 0.738 grams of helium and 8.98 grams of nitrogen. T
Andrei [34K]

Answer:

The partial pressure of nitrogen in the flask is 1.08 atm and the total pressure in the flask is 1.70 atm.

Explanation:

We must use the Ideal Gas Law to solve this:

Pressure . volume = n . R . T

T = T° in K → T°C + 273

17°C + 273 = 290K

n = moles

In a mixture, n is the total moles (Sum of each mol, from each gas)

Moles = Mass / Molar mass

Moles He = 0.738 g /  4g/m = 0.184 moles

Moles N₂ = 8.98 g / 28g/m = 0.320 moles

0.184 m + 0.320m = 0.504 moles

P . 7.03L = 0.504m . 0.082L.atm/ mol.K . 290K

P = (0.504m . 0.082L.atm/ mol.K . 290K) /7.03L

P = 1.70 atm  - This is the total pressure.

To know the partial pressure of N₂ we can apply, the molar fraction:

Moles of N₂ / Total moles = Pressure N₂ / Total pressure

0.320m / 0.504m = Pressure N₂ / 1.70atm

(0.320m / 0.504m) . 1.70atm = Pressure N₂

1.08atm = Pressure N₂

8 0
4 years ago
What are the three elements found in a molecule of calcium carbonate? Give their atomic numbers and chemical symbols. How many a
Thepotemich [5.8K]
Calcium carbonate is CaCO3.
So there is calcium, symbol is Ca and an atomic number of 20.
Carbon: symbol is C and an atomic number of 6.
Oxygen: symbol is O and an atomic number of 8.
In one molecule of CaCO3, there is one atom of Ca, one atom of C, and three atoms of O as shown by the subscript next to O in the formula. There are no other subscripts to indicate more than one atom of the other elements, so there is only one atom of the other two elements
7 0
3 years ago
How many grams of calcium phosphate can be produced when 78.5 grams of calcium hydroxide reacts with excess phosphoric acid? Unb
emmainna [20.7K]
The balanced chemical equation is written as :
2H3PO4 + 3Ca(OH)2 → 6H2O + Ca3(PO4)2.
________
From the above equation we can see that 3 moles of Ca(OH)2 produces 1 mole Ca3(PO4)2 .
( Don't take tension about H3PO4 as it is present in excess )
_________
Further ,
we are given 78.5 g Ca(OH)2 .
then no of moles Ca(OH)2 given = 78.5/74 = 1.06 moles.
________
3 moles Ca(OH)2 produces → 1 mole Ca3(PO4)2.
=> 1 mole Ca(OH)2 produces → 1/3 mole Ca3(PO4)2.
=> 1.06 mole Ca(OH)2 produces → (1/3)×1.06 mole Ca3(PO4)2.
Hence number of moles Ca3(PO4)2 produced = (1/3)×1.06 = 0.353 moles.
________
Now gram molecular mass of Ca3(PO4)2 is = 310 g /mole .
hence grams of Ca3(PO4)2 produced
= 0.353× 310 = 109.43 g
________
Hope it helps...

8 0
3 years ago
Read 2 more answers
200 mL of water is added to 700 mL of a 3-M NaCl solution. What is the concentration of the diluted solution?
liberstina [14]

Answer:

2.3 M

Explanation:

First we calculate the final volume of the solution:

  • Final Volume = 200 mL + 700 mL
  • Final Volume = 900 mL

With the final volume we can use a <em>dilution factor</em> to c<u>alculate the concentration of the diluted solution</u>:

  • Original Concentration * Initial Volume / Final Volume = Final Concentration
  • 3 M * 700 mL / 900 mL = 2.3 M
4 0
3 years ago
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