Answer: Acceleration = 5m/s^2; Distance traveled = 320 m
Explanation:
Velocity of car = 40m/s
Time taken = 8 seconds
Acceleration = ?
Distance traveled = ?
A) Since acceleration is the rate of change of velocity per unit time
i.e acceleration = velocity / time
acceleration = 40m/s / 8 seconds
Acceleration = 5m/s^2
B) To get how far the car traveled before stopping, obtain the distance from the formula:
velocity = distance traveled / time
40m/s = distance / 8 seconds
Distance = 40m/s x 8 seconds
Distance = 320 m
Thus, the car’s acceleration is 5m/s^2 while it traveled 320 metres before stopping.
Answer: 586.60N/m
Explanation:
In this scenario, the elastic potential energy of the spring is converted into potential energy.
0.5*K*x^2 = mgh
Thus K = 2mgh/x^2
=(2*2.90*10^-2*9.8*7.23)/(8.37*10^-2)^2
=586.599
Therefore K = 586.60N/m
Answer:
The number of neutrons.
Explaination:
The atoms of carbon 12 contain 6 neutrons while the atoms of carbon 14 contain 8 neutrons
Answer:
Distance traveled during this acceleration will be 6950 m
Explanation:
Wear have given maximum speed tat will be equal to final speed of the car v = 278 m/sec
Constant acceleration 
As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec
From third equation of motion 
Putting all values in equation
s = 6950 m
So distance traveled during this acceleration will be 6950 m
