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3 years ago

What is the most destructive storm on earth

Physics

2 answers:

SIZIF [17.4K]3 years ago

7 0

Hurricanes i believe

Alona [7]3 years ago

7 0

I believe it to be Hurricanes , not positive though ;)

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Run Gizmo: Orbital velocity is the velocity needed to make a circular orbit. Use the Gizmo to find the orbital velocity of the b

Lina20 [59]

Answer:

Hmm i need more info

Explanation:

8 0

3 years ago

A sample of an ideal gas is in a tank of constant volume. The sample absorbs heat energy so that its temperature changes from 33

Anuta_ua [19.1K]

Answer:

$\frac{v_{2}}{v_{1}}=2$ .

Explanation:

The average kinetic energy per molecule of a ideal gas is given by:

$\bar{K}=\frac{3k_{B}T}{2}$

Now, we know that $\bar{K} = (1/2)m\bar{v}^{2}$

Before the absorption we have:

$(1/2)m\bar{v_{1}}^{2}=\frac{3k_{B}T_{1}}{2}$ (1)

After the absorption,

$(1/2)m\bar{v_{2}}^{2}=\frac{3k_{B}T_{2}}{2}$ (2)

If we want the ratio of v2/v1, let's divide the equation (2) by the equation (1)

$\frac{v_{2}^{2}}{v_{1}^{2}}=\frac{T_{2}}{T_{1}}$

$\frac{v_{2}}{v_{1}}=\sqrt{\frac{T_{2}}{T_{1}}}$

$\frac{v_{2}}{v_{1}}=\sqrt{\frac{1340}{335}}$

$\frac{v_{2}}{v_{1}}=\sqrt{4}$

Therefore the ratio will be $\frac{v_{2}}{v_{1}}=2$

I hope it helps you!

4 0

4 years ago

Read 2 more answers

The blackbody radation emmitted from a furnace peaks at a wavelength of 1.9 x 10^-6 m (0.0000019 m). what is the temperature ins

krek1111 [17]

Answer:

Temperature, T = 1542.10 K

Explanation:

It is given that,

The black body radiation emitted from a furnace peaks at a wavelength of, $\lambda=1.9\times 10^{-6}\ m$

We need to find the temperature inside the furnace. The relationship between the temperature and the wavelength is given by Wein's law i.e.

$\lambda\propto \dfrac{1}{T}$

$\lambda=\dfrac{b}{T}$

b = Wein's displacement constant

$\lambda=\dfrac{2.93\times 10^{-3}}{T}$

$T=\dfrac{2.93\times 10^{-3}}{\lambda}$

$T=\dfrac{2.93\times 10^{-3}}{1.9\times 10^{-6}\ m}$

T = 1542.10 K

So, the temperature inside the furnace is 1542.10 K. Hence, this is the required solution.

3 0

3 years ago

Two speakers both emit sound of frequency 320 Hz, and are in phase. A receiver sits 2.3 m from one speaker, and 2.9 m from the o

satela [25.4K]

Answer:

Option B

Explanation:

The phase difference is found by subtracting the 2.3m for the receiver from the other speaker which is 2.9m hence

Phase difference= 2.9-2.3= 0.6

3 0

3 years ago

Sound wave W has amplitude ‘A' and frequency ‘f'. Sound wave X is louder and lower in pitch than sound wave W. What can be said

ra1l [238]

Answer:

Sound wave X amplitude is greater than 'A' and its frequency is lesser than

'f'

Explanation:

The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.

A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.

The larger the amplitude of the waves, the louder the sound and vice-versa.

From the question,

Sound wave W has amplitude ‘A' and frequency 'f' and

Sound wave X is louder and lower in pitch than sound wave W.

Since sound wave X is louder, this means its amplitude is greater than 'A'.

Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.

7 0

3 years ago