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tatyana61 [14]
3 years ago
14

what is relative velocity in one dimension if va and vb are the velocities of two body a and b respectively then prove vab=va -v

b
Physics
1 answer:
motikmotik3 years ago
3 0

Answer:

Relative velocity is nothing but the velocity of one body with respect to the velocity of some other body.  

Explanation:

Relative velocity may be defined as the rate at which the change of separation takes place between any two object.The relative velocity of any object A w.r.t. another object B when they are in motion is nothing but the rate of change of their position from one another.

Now, let the velocity of object A be  $ v_A$

         and velocity of object B is $ v_B$

Therefore, relative velocity of a object A when compared to the velocity of object B is given by $v_{AB}=v_A - v_B$.

         

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The law of reflection is quite useful for mirrors and other flat, shiny surfaces. (This sort of reflection is called specular re
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Answer:

Explanation:

Suppose initially the plane was horizontal and light was reflected back at some angle θ from the normal .

Now the reflecting surface is twisted so that is becomes inclined at angle alpha .

The reflected light will be deviated from its original direction by angle

2 x alpha .

Similarly when the reflecting surface is further twisted so that it becomes inclined at angle beta then again the reflected beam will deviated by angle

2 x beta

Hence angle between these two reflected beam

= 2 beta - 2 alpha

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So, angular separation between the rays reflected from the two surfaces

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5 0
3 years ago
A particular circuit toolbox contains only 80 Ω resistors and switches, which can be open or closed. Construct a circuit, fillin
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Answer:

Here we need to make parallel connection of two 80 ohm resistors to achieve 40 ohm net resistance.

Explanation:

As we know that the resistances in series add up directly and here we are given with only the resistors of 80 Ω.

So when we connect two resistors of 80 ohm in parallel we get the resultant of 40 ohm.

Mathematically:

\frac{1}{R_p} =\frac{1}{R} +\frac{1}{R}

\frac{1}{40} =\frac{1}{R} +\frac{1}{R}

\frac{1}{40} =\frac{2}{R}

R=80\Omega gives us the only combination of two resistors in parallel.

3 0
3 years ago
An object ends up at a final position of x=-55.25 meters after a displacement of -189.34 meters after a displacement of -189.34
Travka [436]

The initial position of the object was found to be 134.09 m.

<u>Explanation:</u>

As displacement is the measure of difference between the final and initial points. In other words, we can say that displacement can be termed as the change in the position of the object irrespective of the path followed by the object to change the path. So

Displacement = Final position - Initial position.

As the final position is stated as -55.25 meters and the displacement is also stated as -189.34 meters. So the initial position will be

Initial position of the object = Final position-Displacement

Initial position = -55.25 m - (-189.34 m) = -55.25 m + 189.34 m = 134.09 m.

Thus, the initial position for the object having a displacement of -189.34 m is determined as 134.09 m.

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When two positive charges are brought close together, what happens to the
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Answer:

they will move away from each other

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When and where was the worst hurricane in the united states
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It was in Texas on September 8, 1900.
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