what is relative velocity in one dimension if va and vb are the velocities of two body a and b respectively then prove vab=va -v
1 answer:
Answer:
Relative velocity is nothing but the velocity of one body with respect to the velocity of some other body.
Explanation:
Relative velocity may be defined as the rate at which the change of separation takes place between any two object.The relative velocity of any object A w.r.t. another object B when they are in motion is nothing but the rate of change of their position from one another.
Now, let the velocity of object A be
and velocity of object B is
Therefore, relative velocity of a object A when compared to the velocity of object B is given by .
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Answer:
w = √ 1 / CL
This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence
Explanation:
This problem refers to electrical circuits, the circuits where this phenomenon occurs are series RLC circuits, where the resistor, the capacitor and the inductance are placed in series.
In these circuits the impedance is
X = √ (R² + ( -
)² )
where Xc and XL is the capacitive and inductive impedance, respectively
X_{C} = 1 / wC
X_{L} = wL
From this expression we can see that for the resonance frequency
X_{C} = X_{L}
the impedance of the circuit is minimal, therefore the current and voltage are maximum and an increase in signal intensity is observed.
This does not violate energy conservation because the voltage of the power source is equal to the voltage drop in the resistence
V = IR
Since the contribution of the two other components is canceled, this occurs for
X_{C} = X_{L}
1 / wC = w L
w = √ 1 / CL
Answer:
0.1 rev/s
Explanation:
M = mass of the merry go round = 200 kg
R = radius of merry go round = 6 m
= Moment of inertia of merry go round = (0.5) MR² = (0.5) (200) (6)² = 3600 kgm²
m = mass of the man = 100 kg
= Moment of inertia of merry go round when man sits on it at the edge = (0.5) MR² + mR² = (0.5) (200) (6)² + (100) (6)² = 7200 kgm²
= initial Angular speed of merry-go-round before man sit = 0.2 rev/s
= Angular speed of merry-go-round after man sit = ?
Using conservation of angular momentum
=
(3600) (0.2) = (7200)
= 0.1 rev/s