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Alex Ar [27]
3 years ago
9

Two movers push horizontally on a refrigerator. One pushes due north with a force of 150 N and the other pushes due east with a

force of 200 N. Find the direction and magnitude of the resultant force on the refrigerator.
Physics
1 answer:
sammy [17]3 years ago
4 0

Answer:

R=250 N

α = 38.86⁰

Explanation:

Given that

Force ,F₁ = 150 N (Towards north  )

Force ,F₂ = 200 N ( Towards east )

We know that the angle between north and east direction is 90⁰ .

The resultant force R is given as

R=\sqrt{F_1^2+F_2^2+2F_1F_2cos\theta\\

We know that

cos 90⁰ =  0

That is why

R=\sqrt{150^2+200^2}\\R=250\ N

Therefore the magnitude of the forces will be 250  N.

The angle  from the horizontal of the resultant force = α

tan\alpha=\dfrac{150}{200}\\tan\alpha=0.75\\\alpha=38.86\ degrees

R=250 N

α = 38.86⁰

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According to quantum physics, measuring velocity of a tiny particle with an electromagnet
lidiya [134]

Answer:

Option A.

Explanation:

In quantum physics <u>there is a law to relate the position and the momentum of the particle</u>, it says that if we know with precision where is a quantum particle, we can not know the momentum of this particle, in other words, the velocity of the particle. So, when we measure the velocity of the particle we find the correct value of the particle, but we can not determine with accuracy where is the particle. This law is known as the Heisenberg's uncertainty principle and, its expressed as follows:    

\Delta x \Delta p \geq \frac{h}{4 \pi}

<em>where Δx: is the position's uncertainty, Δp: is the momentum's uncertainty and h: is the Planck constant.</em>  

Therefore, the correct answer is A: measuring the velocity of a tiny particle with an electromagnet has no effect on the velocity of the particle. It only affects the determination of the particle's position.      

I hope it helps you!

4 0
3 years ago
An 85-kg man plans to tow a 109 000-kg airplane along a runway by pulling horizontally on a cable attached to it. Suppose that h
Lelu [443]

Answer:

The greatest acceleration the man can give the airplane is 0.0059 m/s².

Explanation:

Given that,

Mass of man = 85 kg

Mass of airplane = 109000 kg

Distance = 9.08

Coefficient of static friction = 0.77

We need to calculate the greatest friction force

Using formula of friction

F=\mu mg

Where, m = mass of man

g = acceleration due to gravity

Put the value into the formula

F = 0.77\times85\times9.8

F= 641.41\ N

We need to calculate the acceleration

Using formula of newton's second law

F = ma

a=\dfrac{F}{m}

Put the value into the formula

a=\dfrac{ 641.41}{109000}

a=0.0059\ m/s^2

Hence, The greatest acceleration the man can give the airplane is 0.0059 m/s².

3 0
3 years ago
Concave lens cause rays to _____.
Molodets [167]
Diverge or spread apart.
5 0
3 years ago
Graphing Motion
KIM [24]
The answer will be D
3 0
4 years ago
A student connects a 1 hp motor to a bicycle. How much time will it take for the bicycle to accelerate from rest to a speed of 5
bija089 [108]

Answer:

t=2s

Explanation:

The definition of power is:

P=\frac{W}{t}

And the work-energy theorem states that:

W=\Delta K

Since the movement starts from rest, we have that:

\Delta K=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}=\frac{mv_f^2}{2}

And putting all together:

P=\frac{mv_f^2}{2t}

Since we want the time taken:

t=\frac{mv_f^2}{2P}

Which for our values is:

t=\frac{(120kg)(5m/s)^2}{2(746W)}=2s

7 0
4 years ago
Read 2 more answers
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