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dem82 [27]
3 years ago
13

Why do solids have a definite shape?

Physics
2 answers:
ddd [48]3 years ago
5 0
Any matter that is a solid<span> has a </span>definite shape<span> and a </span>definite<span> volume. The molecules in a </span>solid<span> are in fixed positions and are close together. Although the molecules can still vibrate, they cannot move from one part of the </span>solid<span> to another part. As a result, a </span>solid does<span> not easily change its </span>shape<span> or its volume</span>
Rashid [163]3 years ago
4 0
"any matter that is a solid has a definite shape and a definite volume. the molecules in a solid are in fixed positions and are close together, although the molecules can still vibrate they cannot move from one part of the solid to another part. as a result, a solid does not easily change its shape or its volume."

I hope this helps ^-^
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You decide to roll a 0.11-kgkg ball across the floor so slowly that it will have a small momentum and a large de Broglie wavelen
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3 0
1 year ago
You stand on a merry-go-round which is spinning at f = 0:25 revolutions per second. You are R = 200 cm from the center. (a) Find
ivanzaharov [21]

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

<u>ω = 1.57 rad/s </u>

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

<u>ac = 4.92 m/s² </u>

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

<u>μs = 0.5</u>

7 0
2 years ago
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