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dem82 [27]
3 years ago
13

Why do solids have a definite shape?

Physics
2 answers:
ddd [48]3 years ago
5 0
Any matter that is a solid<span> has a </span>definite shape<span> and a </span>definite<span> volume. The molecules in a </span>solid<span> are in fixed positions and are close together. Although the molecules can still vibrate, they cannot move from one part of the </span>solid<span> to another part. As a result, a </span>solid does<span> not easily change its </span>shape<span> or its volume</span>
Rashid [163]3 years ago
4 0
"any matter that is a solid has a definite shape and a definite volume. the molecules in a solid are in fixed positions and are close together, although the molecules can still vibrate they cannot move from one part of the solid to another part. as a result, a solid does not easily change its shape or its volume."

I hope this helps ^-^
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In a simple series circuit, why does the bulb light up when you close the switch
photoshop1234 [79]
<span>closing the switch completes the circuit</span>
8 0
4 years ago
What kind of weather system encourages a thunderstorm to develop
valentina_108 [34]
Low pressure systems
6 0
4 years ago
When radioactive tracers are used for medical scans, the tracers both decay in the body via radiation, as well as being excreted
irinina [24]

Answer:

Effective half-time of the tracer is 3.6 days

Explanation:

The formula for calculating the decay due to excretion for the first process is ;

\frac{dN_1}{dt } = - \lambda _e N_o

here ;

N_o = initial number of tracers

Then to the second process ; we have :

\frac{dN_2}{dt } = - \lambda _e N_o

The total decay is as a result of the overall process occurring ; we have :

\frac{dN_{total}}{dt } = \frac{dN_1}{dt} + \frac{dN_2}{dt}   ------ (1)

here ;

\frac{dN_{total}}{dt } = \lambda _{total} N_o

Putting the values in (1);we have :

- \lambda _{Total} N_o = - \lambda_e N_o + ( -\lambda r N_o})

\lambda _{Total} = \lambda_e + \lambda r

As we also know that:

\frac{1}{t_{1/2}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}

\frac{1}{t_{1/2}}_{effective}} = \frac{[t_{1/2}]_{radiation}+[t_{1/2}]_{excretion}}{[t_{1/2}]_{radiation}*[t_{1/2}]_{excretion}}

\frac{1}{t_{1/2}}_{effective}} = \frac{9+6}{9*6}

\frac{1}{t_{1/2}_{effective}}}=\frac{15}{54}

t_{1/2}_{effective}} = \frac{54}{15}

= 3.6 days

5 0
4 years ago
Read 2 more answers
A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (1.40
leva [86]

Answer:

The work done required on the coin during the displacement is 21.75 w.

Explanation:

Given that,

A coin slides over a friction-less plane i.e friction force = 0.

The co-ordinate of the given point is (1.40 m, 7.20 m).

The position vector of the given point is represented by  1.40 \hat i+7.20 \hat j.

The displacement of the coin is

\vec d=1.40 \hat i+7.20 \hat j

The force has magnitude 4.50 N and its makes an angle 128° with positive x axis.

Then x component of the force = 4.50 cos128°

The y component of the force = 4.50 sin128°

Then the position vector of the force is

\vec F=(4.50 cos 128^\circ)\hat i+(4.50 sin 128^\circ)\hat j

   =-2.77 \hat i+3.56 \hat j

We know that,

work done is a scalar product of force and displacement.

W=\vec F.\vec d

    =(-2.77 \hat i+3.56 \hat j).(1.40 \hat i+7.20 \hat j)

    =(-2.77×1.40+ 3.56×7.20) w

    =21.75 w

The work done required on the coin during the displacement is 21.75 w.

6 0
3 years ago
The area under the line and above the axes on a velocity vs. time graph represents what?
galben [10]

Area under the line and above the axis on a velocity - time graph represents the displacement of the object.

8 0
3 years ago
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