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3 years ago

Air pressures for thunderstorms

Chemistry

1 answer:

aliina [53]3 years ago

7 0

Answer:

Explanation:

The typical baseline reading is done at sea level, where 14.7 pounds of pressure per square inch of air will raise the mercury level to 29.53 inches. Air pressure falls as the elevation rises

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For the wild type (unmutated) enzyme, you measure a rate of p-nitrophenol release by the change in absorbance at 405 nm (for the

Aleks04 [339]

Answer:

1.2x10⁻⁵M = Concentration of the product released

Explanation:

Lambert-Beer's law states the absorbance of a solution is directly proportional to its concentration. The equation is:

A = E*b*C

<em>Where A is the absotbance of the solution: 0.216</em>

<em>E is the extinction coefficient = 18000M⁻¹cm⁻¹</em>

<em>b is patelength = 1cm</em>

<em>C is concentration of the solution</em>

<em />

Replacing:

0.216 = 18000M⁻¹cm⁻¹*1cm*C

<h3>1.2x10⁻⁵M = Concentration of the product released</h3>

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3 years ago

Which representative element has the largest atomic radius ?

Vikki [24]

Answer:

francium

Explanation:

the atomic radius increases from top to bottom in a group, and decreases from left to right across a period.

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3 years ago

Density is ___ to pressure

Ann [662]

Proportional to pressure

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3 years ago

The principal source of sulfur on earth is deposits of free sulfur occurring mainly in volcanically Active regions. The offer wa

aivan3 [116]

Answer:

1.18x10⁸L of SO₂ and 2.36x10⁸L of H₂S

Explanation:

The balanced reaction is:

8SO₂(g) + 16H₂S(g) → 16H₂O(l) + 3S₈(s)

To solve this question we must find the moles of S₈ in 4.50x10⁵kg. With these moles and the reaction we can find the moles of SO₂ needed to react (Twice these moles = Moles Of H₂S needed). Using PV = nRT we can find the volume of the gas required:

<em>Moles S₈ - molar mass: 256.52g/mol-</em>

4.50x10⁵kg = 4.50x10⁸g * (1mol / 256.52g) =

1.75x10⁶ moles S₈

<em>Moles SO₂:</em>

1.75x10⁶ moles S₈ * (8mol SO₂ / 3mol S₈) = 4.68x10⁶ moles SO₂

<em>Moles H₂S:</em>

4.68x10⁶ moles SO₂ * 2 = 9.36x10⁶ moles H₂S

The volume could be obtained as follows:

PV = nRT

V = nRT / P

<em>V is volume in liters</em>

<em>n are moles: 4.68x10⁶ moles SO₂ and 9.36x10⁶ moles H₂S</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 22°C + 273.15 = 295.15K</em>

<em>P is pressure = 0.961atm</em>

<em />

Replacing:

Volume SO₂ and H₂S:

4.68x10⁶ moles * 0.082atmL/molK * 295.15K / 0.961atm =

<em>9.36x10⁶ moles H₂S</em> * 0.082atmL/molK * 295.15K / 0.961atm =

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3 years ago

If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence

ValentinkaMS [17]

Answer:

$M_{base}=0.173M$

Explanation:

Hello there!

In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

$n_{acid}=M_{base}V_{base}$

Thus, by solving for the volume of the base as NaOH, we obtain:

$M_{base}=\frac{n_{acid}}{V_{base}} \\\\M_{base}=\frac{0.8675g*\frac{1mol}{204.22g} }{0.02456L} \\\\M_{base}=0.173M$

Best regards!

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3 years ago