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Olegator [25]
3 years ago
10

The intensity of the waves from a point source at a distance d from the source is I. At what distance from the sources is the in

tensity equal to 2I
Physics
1 answer:
Oliga [24]3 years ago
8 0

Answer:d'=\frac{d}{\sqrt{2}}

Explanation:

Intensity of the waves from a point source can be given by Power divided by surface area.

For P Power source and at a distance d from source Intensity is given by

I=\frac{P}{\pi\cdot d^2}--------1

when intensity is 2I then it is at a distance of let say d'

2I=\frac{P}{\pi\cdot d'^2}--------2

Divide 1 and 2 we get

\frac{I}{2I}=\frac{P}{\pi\cdot d^2}\times \frac{\pi\cdot d'^2}{P}

\frac{1}{2}=(\frac{d'}{d})^2

\frac{d'}{d}=\frac{1}{\sqrt{2}}

d'=\frac{d}{\sqrt{2}}

     

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Answer:

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Explanation:

5 0
3 years ago
A 2.0-kg projectile is fired with initial velocity components v0x = 30 m/s and v0y = 40 m/s from a point on the Earth's surface.
EleoNora [17]

(a) The kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.

(b) The work done  in firing the projectile is 2,500 J.

<h3>Kinetic energy of the projectile at maximum height</h3>

The kinetic energy of the projectile when it reaches the highest point in its trajectory is calculated as follows;

K.E = ¹/₂mv₀ₓ²

where;

  • m is mass of the projectile
  • v₀ₓ is the initial horizontal component of the velocity at maximum height

<u>Note:</u> At maximum height the final vertical velocity is zero and the final horizontal velocity is equal to the initial horizontal velocity.

K.E = (0.5)(2)(30²)

K.E = 900 J

<h3>Work done in firing the projectile</h3>

Based on the principle of conservation of energy, the work done in firing the projectile is equal to the initial kinetic energy of the projectile.

W = K.E(i) = ¹/₂mv²

where;

  • v is the resultant velocity

v = √(30² + 40²)

v = 50 m/s

W = (0.5)(2)(50²)

W = 2,500 J

Thus, the kinetic energy of the projectile when it reaches the highest point in its trajectory is 900 J.

The work done  in firing the projectile is 2,500 J.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

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2 years ago
A man is pushing a heavy crate up an inclined plane (ramp) into the back of semi trailer. What can the man do to make it easier
strojnjashka [21]
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6 0
3 years ago
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GrogVix [38]

Answer: perpendicular to it oscillations.

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By perpendicular, we mean that the wave is oscillating on the vertical axis (y) of a Cartesian plane and the vibration is along the horizontal axis (x) of the plane.

Examples of transverse waves includes wave in a string, water wave and light.

Let us take a wave in a string for example, you tie one end of a string to a fixed point and the other end is free with you holding it.

If you move the rope vertically ( that's up and down) you will notice a kind of wave traveling away from you ( horizontally) to the fixed point.

Since the oscillations is perpendicular to the direction of wave, it is a transverse wave

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3 years ago
What is the kinetic energy of a 8kg cat running 5m/s?
ivanzaharov [21]
<span>K.E = 0.5 * m * v^2 ( m = mass(Kg), V = Velocity(m/s)
= 0.5 * 8 * 5^2
= 4 * 25
= 100 J </span>
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4 years ago
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