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3 years ago

The Celsius temperature scale is based on which of the following

Physics

2 answers:

Anestetic [448]3 years ago

8 0

Answer:

A. the boiling and freezing point of water

Explanation:

The Celsius Temperature scale is based on the boiling and freezing point of water.

0° Celsius is know as freezing point of water and 100° C is known as the boiling point of boiling point of water. It was developed by a Swedish scientist named Anders Celsius. It is also sometimes called Centigrade scale.

saw5 [17]3 years ago

6 0

The boiling and freezing point of water. You know this because at 0degrees water freezes and at 100 degrees water boils

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A joule is used to measure a. power. b. energy. c. torque. d. pressure.

KATRIN_1 [288]

The Joule is the SI unit of energy.

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3 years ago

Is the furnace an internal or external combustion engine

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3 years ago

Yellow light of wavelength 590 nm passes through a diffraction grating and makes an interference pattern on a screen 80 cm away.

riadik2000 [5.3K]

Answer:B

Explanation:

Given

Wavelength of light $\lambda =590\ nm$

Screen distance $L=80\ cm$

First fringe is at a distance $y_1=1.9\ cm$

No of lines per mm is given by N

$N=\frac{1}{d}$

where d=slit width

From N-slits Experiment

$\sin \theta _m=\frac{m\lambda }{d}$

$d=\frac{m\lambda }{\sin \theta _m}-----1$

Position of bright fringe is given by

$y=\tan \theta _m\cdot L$

$\tan \theta _m=\frac{y}{L}$

$\theta _m=\tan^{-1}(\frac{y}{L})$

Put the value of $\theta _m$ in eq. 1

$d=\frac{m\lambda }{\sin (\tan^{-1}(\frac{y}{L}))}$

Therefore $N=d^{-1}$

$N=\frac{\sin (\tan^{-1}(\frac{y}{L}))}{m\lambda }$

for $m=1$

$N=\frac{\sin (\tan^{-1}(\frac{1.9\times 10^{-2}}{0.8}))}{1\times 590\times 10^{-9}}$

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$N=40\ line/mm$

4 0

4 years ago

Someone please help me

Trava [24]

Answer:

The answer to your question is: D) Ф₂ = 49.71°

Explanation:

Data

n₁ = 1.33

Ф₁ = 35°C

n₂ = 1

Ф₂ = sin⁻¹ (n₁ sinФ₁/n₂)

Process

Substitution

Ф₂ = sin⁻¹ (n₁ sinФ₁/n₂)

Ф₂ = sin⁻¹ (1.33 sin 35/1)

Ф₂ = sin⁻¹ (1.33 x 0.574/ 1)

Ф₂ = sin⁻¹ ( 0.7628 / 1)

Ф₂ = sin⁻¹ (0.7628)

Ф₂ = 49.71°

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3 years ago

The diagram shows the scales used for recording

padilas [110]

Answer: 212

Explanation:

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3 years ago