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Ronch [10]
3 years ago
12

Tell how electromagnetic waves differ from mechanical waves

Physics
1 answer:
Fudgin [204]3 years ago
3 0
<span>Electromagnetic and mechanical waves differ in that electromagnetic waves are always longitudinal and do not require a known medium, while mechanical waves are either longitudinal or compression waves and require a medium. All known electromagnetic waves are also known as forms of light.</span>
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What property do protons can electrons have that neutrons do not ?
Vesna [10]

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Protons and electrons are charged particles. Neutrons have no charge.

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Do you think radio waves and x-rays are types of light?
goblinko [34]

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yes, radio waves and x-rays are type of light.

6 0
3 years ago
Read 2 more answers
Kenny klutz drops his physics book off his aunt's high-rise balcony.it hits the ground below 1.5 s later?
tatuchka [14]

Gravity causes a falling object to fall 9.8 m/s faster every second it falls.

Kenny's book started out with no speed when it was dropped. 
1.5 sec later, it was falling at (9.8 x 1.5) = 14.7 m/s .

During the fall, its average speed was  1/2(0 + 14.7) = 7.35 m/s .

Distance it covered = (average speed) x (time) =

                                             (7.35 m/s) x (1.5 sec) = 11.025 m

8 0
3 years ago
A skater of mass 60 kg has an initial velocity of 12 m/s. He slides on ice where the frictional force is 36 N. How far will the
Alexus [3.1K]

Answer:

d = 120 [m]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. Where the energy in the final state (when the skater stops) is equal to the sum of the mechanical energy in the initial state plus the work done on the skater in the initial state.

The mechanical energy is equal to the sum of the potential energy plus the kinetic energy.  As the track is horizontal there is no unevenness, in this way, there is no potential energy.

E₁ + W₁₋₂ = E₂

where:

E₁  = mechanical energy in the initial state [J] (units of Joules)

W₁₋₂ = work done between the states 1 and 2 [J]

E₂  = mechanical energy in the final state = 0

E₁ = Ek = kinetic energy [J]

E₁ = 0.5*m*v²

where:

m = mass = 60 [kg]

v = initial velocity = 12 [m/s]

Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.

W₁₋₂ = -f*d

where:

f = friction force = 36 [N]

d = distance [m]

Now we have:

0.5*m*v² - (f*d) = 0

0.5*60*(12)² - (36*d) = 0

4320 = 36*d

d = 120 [m]

7 0
3 years ago
A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67
egoroff_w [7]

Answer:

6.22 N/m

Explanation:

From Hooke's law we deduce that F=kx where F is the applied force and k is the spring constant while x is the extension or compression of the spring. Making k the subject of the above formula then

k=\frac {F}{x}

We also know that the force F is equal to mg where m is the mass of an object and g is acceleration due to gravity hence substituting F with mg we get that

k=\frac {mg}{x}

Substituting m with 425 g which is equivalent to 0.425 kg and g with 9.81 then 0.67 for x we get that

k=\frac {mg}{x}=\frac {0.425\times 9.81}{0.67}=6.222761194 N/m\approx 6.22\ N/m

Therefore, the spring constant is approximately 6.22 N/m

3 0
4 years ago
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