Explanation:
It is given that,
Mass of the passenger, m = 75 kg
Acceleration of the rocket, 
(a) The horizontal component of the force the seat exerts against his body is given by using Newton's second law of motion as :
F = m a
F = 3675 N
Ratio, 
So, the ratio between the horizontal force and the weight is 5 : 1.
(b) The magnitude of total force the seat exerts against his body is F' i.e.
F' = 3747.7 N
The direction of force is calculated as :
Hence, this is the required solution.
I’ve answered this problem before and there were 2 parts in
this problem.
The solution would be like this for this specific problem:
<span>A.
</span><span>Vf = Vi +
Vex*ln(Mi / Mf) </span><span>
<span>0.002 * 3e8m/s = 0 + 2000m/s * ln(Mi / Mf) </span>
<span>300 = ln(Mi / Mf) </span>
<span>1.9e130 = Mi / Mf </span></span>
<span>B.
</span><span>4000m/s =
2000m/s * ln(Mi / Mf) </span><span>
<span>2 = ln(Mi / Mf) </span>
<span>7.389 = Mi / Mf </span>
<span>Mf = Mi / 7.389 = 0.135*Mi<span> </span></span></span>
This shifts chemical equilibria toward the products or reactants, which can be determined by studying the reaction and deciding whether it is endothermic or exothermic....
Superconductor, conductor, semiconductor, insulator
There are several information's of immense importance already given in the question. The answer to the question can be easily determined using those available information's.
Mr of pure tungsten = 183.84
Mass of tungsten = Mole * Mr
= 0.7 * 183.84
= 128.7 gm
From the above deduction, it can be concluded that the correct option among all the options that are given in the question is the third option or the penultimate option.
