Answer:
The plane would need to travel at least
(
.)
The
runway should be sufficient.
Explanation:
Convert unit of the the take-off velocity of this plane to
:
.
Initial velocity of the plane:
.
Take-off velocity of the plane
.
Let
denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation
.
Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration
times average velocity
.
The distance that the plane need to cover would be:
.
1. Volume of the solution (B)
2. Celery (D)
3. Hydroxide ions in solution (A)
Complete Question
The complete question is shown on the first uploaded image
Compare the percent error between your value and the accepted value of 1.26 times 10-6 T · m/A. (Use the accepted value given to three significant figures in your calculation.). 100% % error = %
Answer:
The permeability of free space is ![\mu_0 = 1.32*10^{-6} \ Tm/A](https://tex.z-dn.net/?f=%5Cmu_0%20%3D%201.32%2A10%5E%7B-6%7D%20%5C%20Tm%2FA)
The percentage error is % error = 5.25%
Explanation:
From the question we are told that
The slope is
, and
Generally ![1 \ gauss = 10^{-4 } tesla](https://tex.z-dn.net/?f=1%20%5C%20gauss%20%3D%20%2010%5E%7B-4%20%7D%20tesla)
So ![s = 3.9 *10^ {-4} T /A](https://tex.z-dn.net/?f=s%20%3D%203.9%20%2A10%5E%20%7B-4%7D%20T%20%2FA)
From the relation given in the question
![\mu_0 = \frac{2R}{N} [\frac{B}{I} ]](https://tex.z-dn.net/?f=%5Cmu_0%20%3D%20%5Cfrac%7B2R%7D%7BN%7D%20%5B%5Cfrac%7BB%7D%7BI%7D%20%5D)
Where R is the radius of the coil ![=\frac{Diameter \ of \ coil }{2} = 0.017m](https://tex.z-dn.net/?f=%3D%5Cfrac%7BDiameter%20%5C%20of%20%5C%20coil%20%7D%7B2%7D%20%3D%200.017m)
N is the number of loops of the coil = 10
Now from the question we are told that
![s = \frac{B}{I}](https://tex.z-dn.net/?f=s%20%3D%20%5Cfrac%7BB%7D%7BI%7D)
substituting into the equation above
![\mu_0 = \frac{2R }{N} s](https://tex.z-dn.net/?f=%5Cmu_0%20%3D%20%5Cfrac%7B2R%20%7D%7BN%7D%20s)
Substituting values
![\mu_0= \frac{2 * 0.017}{10 } * 3.9*10^{-4}](https://tex.z-dn.net/?f=%5Cmu_0%3D%20%5Cfrac%7B2%20%2A%200.017%7D%7B10%20%7D%20%2A%203.9%2A10%5E%7B-4%7D)
![= 1.326 *10^ {-6} \ Tm/A](https://tex.z-dn.net/?f=%3D%201.326%20%2A10%5E%20%7B-6%7D%20%5C%20Tm%2FA)
Generally the % error is mathematically represented as
%![error = \frac{Measured \ value - accepted \ value}{accepted \ value } *100](https://tex.z-dn.net/?f=error%20%3D%20%5Cfrac%7BMeasured%20%5C%20%20value%20-%20accepted%20%5C%20value%7D%7Baccepted%20%5C%20%20value%20%7D%20%2A100)
Given that the accepted value is
Hence substituting values
%![error = \frac{(1.326-1.26)*10^{-6}}{1.26 *10 ^ {-6}} *100](https://tex.z-dn.net/?f=error%20%20%3D%20%5Cfrac%7B%281.326-1.26%29%2A10%5E%7B-6%7D%7D%7B1.26%20%2A10%20%5E%20%7B-6%7D%7D%20%2A100)
![= 5.24](https://tex.z-dn.net/?f=%3D%205.24)
Answer:
536.56 m/s
Explanation:
We'll begin by calculating the momentum of the Porsche. This can be obtained as follow:
Mass (m) of Porsche = 1361 kg
Velocity (v) of Porsche = 26.82 m/s
Momentum of Porsche =?
Momentum = mass × velocity
Momentum = 1361 × 26.82
Momentum of Porsche = 36502.02 Kgm/s
Finally, we shall determine the velocity you need to be running with in order to have the same momentum as the Porsche. This can be obtained as follow:
Your Mass = 68.03 kg
Your Momentum = Momentum of Porsche = 36502.02 Kgm/s
Your velocity =?
Momentum = mass × velocity
36502.02 = 68.03 × velocity
Divide both side by 68.03
Velocity = 36502.02 / 68.03
Velocity = 536.56 m/s
Thus you must be running with a speed of 536.56 m/s in order to have the same momentum as Porsche.