Answer:
0.999987
Step-by-step explanation:
Given that
The user is a legitimate one = E₁
The user is a fraudulent one = E₂
The same user originates calls from two metropolitan areas = A
Use Bay's Theorem to solve the problem
P(E₁) = 0.0131% = 0.000131
P(E₂) = 1 - P(E₁) = 0.999869
P(A/E₁) = 3% = 0.03
P(A/E₂) = 30% = 0.3
Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :
= 0.999986898 ≈ 0.999987
Answer:
2,125m
Step-by-step explanation:
85% = 85/100
85/100 = x/2500m
Solve by cross multiplying
85(2500) = 100(x)
212,500 = 100x
Divide by 100 on both sides
x = 2,125m
Hope this helps :)
10 15 20 since i am pretty sure the rest are a triple(definitely 3 4 5 and 7 24 25 is a triple0
There are 64 people in the room.
Since the ratio for women increases 1 when 8 women enter the room, for every time there is 1 in the ratio there are 8 people. That means that originally you have to do 3x8 and 4x8. You get 24 and 32 which equals 56. Then when 8 more women enter the room, you get 64.
