Answer:
The compound moves 6.5 cm in total.
Explanation:
Before solving this problem, let's first write down all lengths we know of from the question:
Starting point of sample = 1.0 cm from bottom of paper
Paper wet up to = 8.8 cm from bottom of paper
Ending point of the sample = 7.5 cm from bottom of paper
With these lengths stated, we can easily calculate the length which the compound moved through:
Length compound moved = Ending point - Starting point
Length compound moved = 7.5 - 1.0
Length compound moved = 6.5 cm
Thus, we can see that the compound moved 6.5 cm between the time the paper was put into, and taken out of the solvent.
Answer:
12J
Explanation:
Given parameters:
Mass = 1.5kg
Impulse = 6kgm/s
let us start first by find the velocity with which this body moves;
Impulse = mass x velocity
Velocity = Impulse / mass = 6/ 1.5 = 4m/s
Initial velocity = 0m/s
Unknown:
Resulting kinetic energy = ?
Solution:
To solve this problem use the formula below:
K.E = m (v - u)²
m is the mass
v is the final velocity
u is the initial velocity
So;
K.E = x 1.5 x (4 - 0)²
K.E = 1.5 x 8 = 12J
The correct option is D.
The critical angle is defined as the angle of incidence, which provides an angle of refraction of 90 degree. At any angle of incidence greater than the critical angle, all the light will totally reflected, resulting in total internal reflection.Thus, the critical angle is equal to the refractive index.
Th equations to be used here are the following:
a = (v - v₀)/t
x = v₀t + 0.5at²
The speed of the fugitive is the sum of his own speed plus the speed of the train. Thus,
v₀ = 0 + 5.5 m/s = 5.5 m/s
v = 8 m/s + 5.5 m/s = 13.5 m/s
a.) We use the first equation to determine time
2.5 m/s² = (13.5 m/s - 5.5 m/s)t
Solving for t,
t = 3.2 seconds
b.) We use the answer in a) and the 2nd equation:
x = (5.5 m/s)(3.2 s) + 0.5(2.5 m/s²)(3.2 s)²
x = 30.4 meters