Female scientist who came to america to study starts at harvard

The period of a 440 Hertz sound wave is __ seconds.

snow_lady [41]

The formula relating frequency and period of a wave is simply frequency = 1 / time. Therefore, by rearranging we also see that time = 1 / frequency. The period of a 440 Hertz sound wave is 1 / 440 seconds. The speed of the wave can also be determined very simply using the formula speed = wavelength x frequency.

8 0

4 years ago

One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s

baherus [9]

Given that,

Central maximum = 1 cm

Distance from the window shade to the wall =4 m

We know that,

The visible range of the sun light is 400 nm to 700 nm.

(a). We need to calculate the average wavelength

Using formula of average wavelength

$\lambda_{avg}=\dfrac{\lambda_{1}+\lambda_{2}}{2}$

Put the value into the formula

$\lambda_{avg}=\dfrac{400+700}{2}$

$\lambda_{avg}=550\ nm$

(b). We need to calculate the diameter of the pinhole

Using formula for diameter

$w=\dfrac{2.44\lambda L}{D}$

$D=\dfrac{2.44\lambda L}{w}$

Put the value into the formula

$D=\dfrac{2.44\times550\times10^{-9}\times4}{1\times10^{-2}}$

$D=0.537\ mm$

Hence, (a). The average wavelength 550 nm.

(b). The diameter of the pinhole is 0.537 mm.

7 0

4 years ago

Sound waves are mechanical waves. Which statement is true for this type of wave?Select one of the options below as your answer:.

Alexandra [31]

By being a Mechanical Wave, which requires a material medium:

D. Sound waves require a medium in order to transport energy

8 0

3 years ago

Read 2 more answers

The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscop

Blababa [14]

Answer:

The focal length of eye piece is 6.52 cm.

Explanation:

Given that,

Angular Magnification of the microscope M = -46

the distance between the lens in microscope L= 16 cm

The focal length of objective f₀ = 1.5 cm

Normal near point N = 25 cm

Have to find focal length of eye piece f ₙ =?

The angular magnification is given by

M ≈ - (L-fₙ)N/f₀fₙ

Rearranging for fₙ

fₙ =L(1 - Mf₀/N)⁺¹

=18/2.76

fₙ = 6.52 cm

The focal length of eye piece is 6.52 cm.

6 0

3 years ago

Calculate the Reynolds number for an oil gusher that shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter

Alenkasestr [34]

Answer:

$Re=1992.24$

Explanation:

Given:

vertical height of oil coming out of pipe, $h=25\ m$

diameter of pipe, $d=0.1\ m$

length of pipe, $l=50\ m$

density of oil, $\rho = 900\ kg.m^{-3}$

viscosity of oil, $\mu=1\ Pa.s$

Now, since the oil is being shot verically upwards it will have some initial velocity and will have zero final velocity at the top.

<u>Using the equation of motion:</u>

$v^2=u^2-2gh$

where:

v = final velocity

u = initial velocity

Putting the respective values:

$0^2=u^2-2\times 9.8\times 25$

$u=22.136\ m.s^{-1}$

<u>For Reynold's no. we have the relation as:</u>

$Re=\frac{\rho.u.d}{\mu}$

$Re=\frac{900\times 22.136\times 0.1}{1}$

$Re=1992.24$

6 0

3 years ago