Answer:
D) 1.61 times faster
Explanation:
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M=17.031 g/mol
√(3)(0.08206)(17.031)= 2.047
= √(3)RTM
R constant= 0.08206
T=constant, so in this problem we dont need a value for it
M= 44.01 g/mol
√(3)(0.08206)(44.01)= 3.29
Since we are trying to measure how much faster NH3 will be, we have to realize that mass and speed have an inverse relationship.
So instead of doing (2.047)/(3.29) = 6.22
we have to flip the values to get (3.29)/(2.047)= 1.61
Answer:
Percentage of Ba in the compound is 19.5%
Explanation:
your answer is Particles collide in gas so Substance X is a gas.
Answer:
The answer to your question is 510.7 kJ
Explanation:
Data
Q = ?
Volume = 2 L
Temperature 1 = T1 = 19°C
Temperature 2 = T2 = 80°C
Specific heat = 4.186 J/kg°C
Density of water = 1 g/ml
Equation
Q = mC(T2 - T1)
Process
1.- Calculate the mass of water
mass = density x volume
mass = 1 x 2000
mass = 2000 g
2.- Substitute values in the Heat formula
Q = (2000)(4.186)(80 - 19)
-Simplification
Q = (2000)(4.186)(61)
-Result
Q = 510692 J or 510.7 kJ
Answer:
The correct answer is B. A compound that is a hydrogen ion acceptor in an acid-base reaction