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Usimov [2.4K]
2 years ago
5

A sample of (NH4)2SO4 contains 0.750 mole. what is the mass of the sample​

Chemistry
1 answer:
steposvetlana [31]2 years ago
5 0
The answer is 99.10.
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Which of the following transitions represent the emission of a photon with the largest energy?
s2008m [1.1K]

Answer:

n=6 to n=3 (B)

Explanation:

Energy of an electron present in the n^{th} orbit is directly proportional to n^{2} .Hence a transistion from one orbit to another orbit emits an energy proportional to the difference of their squares of the orbits. that is if an electron travels from orbit n1 to orbit n2 then it emits an energy corresponding to n_{1} ^{2} -n_{2} ^{2}.So in the above question the highest energy emission occurs when an electron moves from n=6 to n=3.(Highest difference of energy levels).

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3 years ago
Adam observed properties of four different waves and
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Answer:

D)The sound quality for these waves cannot be compared.

Explanation:

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3 years ago
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The diagram below shows different layers of sedimentary rocks.
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D. layer B is younger than layer G.
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If a 100. -g sample of a hydrated compound contains 37.07-g sodium, 48.39-g carbonate and 14.54-g water, find the empirical form
Mumz [18]

he required empirical formula based on the data provided is Na2CO3.H2O.

<h3>What is empirical formula?</h3>

The term empirical formula refers to the formula of a compound which shows the ratio of each specie present.

We have the following;

Mass of sodium = 37.07-g

Mass of carbonate = 48.39 g

Mass of water = 14.54-g

Number of moles of sodium = 37.07-g/23 g/mol = 2 moles

Number of moles of carbonate = 48.39 g/61 g/mol = 1 mole

Number of moles of water = 14.54/18 g/mol = 1 mole

The mole ratio is 2 : 1: 1

Hence, the required empirical formula is Na2CO3.H2O

Learn more about empirical formula : brainly.com/question/11588623

3 0
2 years ago
The decomposition of a compound at 400⁰C is first order with half-life of 1570 seconds. what fraction of an initial amount of th
kirill115 [55]

Answer: After 4710 seconds, 1/8 of the compound will be left

Explanation:

Using the formulae

Nt/No = (1/2)^t/t1/2

Where

N= amount of the compound  present at time t

No= amount of compound present at time t=0

t= time taken for N molecules of the compound to remain = 4710 seconds

t1/2 = half-life of compound  = 1570 seconds

Plugging in the values, we have  

Nt/No = (1/2)^(4710s/1570s)

Nt/No = (1/2)^3

Nt/No= 1/8

Therefore after 4710 seconds, 1/8 molecules of the compound will be left

5 0
3 years ago
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