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Usimov [2.4K]
2 years ago
5

A sample of (NH4)2SO4 contains 0.750 mole. what is the mass of the sample​

Chemistry
1 answer:
steposvetlana [31]2 years ago
5 0
The answer is 99.10.
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Limiting reactants would appreciate the help
Vanyuwa [196]

Answer:

Explanation:

The Limiting Reactant is that reactant which when consumed in a reaction stops the reaction. The other reactants will be in excess and typically considered non-reactive.

To identify the limiting reactant ...

- write and balance the reaction of interest. Express it in standard form. That is, standard form of a reaction is when the coefficients of the balanced equation are in their lowest whole number values. Also, remember that the standard equation is 'assumed' to be at STP conditions (0°C & 1atm).

- convert all given reactant values to moles

- divide each reactant mole value by the related coefficient of the the balanced standard equation. The smaller value is the limiting reactant. The remaining reactants will be in excess.  

Your Problem:

Given:        3Ba  +  N₂  => Ba₃N₂

               22.6g    4.2g        ?

moles Ba => 22.6g/137.34g/mol = 0.165 mole Ba

moles N₂ =>    4.2g/14.007g/mol= 0.150 mole N₂

Part A: Determining the Limited Reactant

  • Divide each mole value by respective coefficient ... smallest value is Limiting  Reactant.

Barium => 0.165/3 = 0.055  <=> (Limiting Reactant)

Nitrogen => 0.15/1 = 0.15

  • Barium is the smaller result and is therefore the limiting reactant. This works for ALL limiting reactant type problems. However, be sure to use the mole values calculated first (Ba = 0.165mol & N₂ = 0.150mol) when doing ratio calculations.

Part B: Max (theoretical) amount of Ba₃N₂ produced:

<em>Note: The product yield amounts are based upon the given 'moles' of limiting reactant, NOT the results of the 'divide by respective coefficient' step used to ID the limiting reactant.     </em>

                   3Ba        +          N₂         =>     Ba₃N₂    (3:1 rxn ratio for Ba:Ba₃N₂)

moles      0.165mole        0.150mole         1/3(0.165)mole = 0.055mole Ba₃N₂

                                                                    = 0.055mol(440g/mol) Ba₃N₂

                                                                    = 24.2 grams Ba₃N₂ (as based

                                                                     upon Barium as Limiting Reactant)

Part C: Excess N₂ remaining after reaction stops:

From balanced standard reaction, the reaction ratio for Ba:N₂ is 3moles:1mole. That is, for the moles of Ba consumed, 1/3(moles of Ba) =  moles of N₂ used.

moles of N₂ used = 1/3(0.165)mole = 0.055mole N₂ used  

∴ the amount of N₂ remaining in excess = 0.150mole (given) - 0.055mole (used) = 0.095mole N₂ remaining in excess.

mass N₂ remaining = 0.095mole x 28g/mole = 2.66 grams N₂ remaining in excess.

                   

5 0
2 years ago
A sample of a gas takes up 2.35L of space at room temperature (20.0ºC). What volume will the gas occupy at -5.00ºC? (Hint: Don’t
sergiy2304 [10]
So if it is 2.35L at the temperature 20.0^C and you want the volume at -5.00^C this is hw you would solve it for example 20.0^C to 2.00L it would be 10 degrees per Liter so it would be here 10 degrees every liter so you would do 20.0 % 2.35 = / then find the answer and then find out how many degrees that answer is off of -5.00 then once you get that divide -5.00 with that answer.<span>
  </span>
3 0
3 years ago
A gas occupies a 1.5 l container at 25 degrees
musickatia [10]
The answer is:

683.8 cm^3
7 0
3 years ago
Calculate the density mass= 54.2 volume= 78.1
Helen [10]

Answer:

0.693 (you can round it up if you want to)

Explanation:

Density= mass ÷ volume

54.2 ÷ 78.1 = 0.693

I hope this helped☺

6 0
2 years ago
Can synthetic chemicals have origins in nature, or are they completely man-made? Give examples and
Aneli [31]
Yes they can have origins in nature. A bunch of the elements on the periodic table are chemicals and this are basic substances and cannot be man made.
6 0
3 years ago
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