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Usimov [2.4K]
2 years ago
5

A sample of (NH4)2SO4 contains 0.750 mole. what is the mass of the sample​

Chemistry
1 answer:
steposvetlana [31]2 years ago
5 0
The answer is 99.10.
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A sample of hydrogen gas collected over water occupied 30.0 mL at 24 °C on a day when the atmospheric pressure was 736 Torr. Wha
givi [52]

Answer:0.026ml

Explanation:

Details are found in the image attached. We must subtract the saturated vapour pressure of hydrogen gas at the given temperature from the total pressure of the hydrogen gas collected over water to obtain the actual pressure of hydrogen gas and substitute the value obtained into the general gas equation. The dry hydrogen gas has no saturated vapour pressure hence the value is substituted as given. All temperatures must be converted to Kelvin before substitution.

4 0
3 years ago
What is the mass percent of nitrogen in ammonium carbonate, (NH4)2CO3?
Margaret [11]

In order for you to calculate for the mass of ammonium carbonate, you need to know the molar mass of it and the nitrogen atoms in the compound. Ammonium carbonate has a molar mass of 96.08 grams per mole. There are two nitrogen atoms in ammonium carbonate which is equal to 28.02 grams per mole. Divide the molar mass of nitrogen to the ammonium carbonate, 28.02/96.08 x 100, we get 29.16wt% nitrogen.

6 0
3 years ago
How many moles are in 25.0 grams of KMnO4?
ElenaW [278]
The answer is: 0.158 mol
You find this by doing:
number of moles (n) = mass (m) / molar mass (M)
n=158.034/25.0
6 0
3 years ago
Why doesnt iron burst into flames when it rusts
Katarina [22]
Rust does not have the properties to catch onto flames. However, if you light it on fire, then it would probably catch in flames but not instantly and will not continue to burn unless you have soaked it in oil or flammable object or substance. :) Hope this helps! 
3 0
3 years ago
Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation: 3NO2(g)+H2O(l)→2HNO3(l)+
Vesnalui [34]

Answer:

2 mol NO2

Explanation:

                                      3NO2(g)+H2O(l)→2HNO3(l)+NO(g)

from reaction                3 mol        1 mol

given                           11 mol          3 mol

for 3 mol NO2  -----   1 mol H2O

for x mol NO2  -----   3 mol H2O

3:x = 1:3

x = 3 *3/1 = 9 mol NO2

So, for 3 mol H2O are needed only 9 mol NO2.

But we have 11 mol NO2. So, NO2 is in excess, and

11 mol NO2 - 9 mol NO2 = 2 mol NO2 will be left after reaction.

3 0
3 years ago
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