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Dmitry_Shevchenko [17]
3 years ago
8

Draw a quick picture to show the number 24.then draw a quick picture to show 24 after you have regrouped 1 ten as 10 ones.

Mathematics
1 answer:
alukav5142 [94]3 years ago
6 0
24   , 1111111111 times 10
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Which is the equation of an asymptote of the hyperbola whose equation is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29x%
tatuchka [14]

The equation of the asymptote is y = 3x - 5. The correct answer is option C

<h3>What is Asymptote of an Hyperbola ?</h3>

The distance from a point and the distance to a line in hyperbola is known as asymptote. The general equation is x^{2}/ a^{2} - y^{2}/b^{2}    = 1

From the given equation of hyperbola, which is

\frac{(x - 2)^{2}}{4}  - \frac{(y - 1)^{2} }{36} = 1

The center (h , k) of the hyperbola = C(2, 1)

a = 2

b = 6

Where C = \sqrt{a^{2} + b^{2}  }

C = \sqrt{4 + 36}

C = \sqrt{40}

C = 2\sqrt{10}

The equation of the asymptote will be y - K = +/-(b/a)(x - h)

That is,

y - 1 = +/-(6/2)(x - 2)

y - 1 = +/-3(x - 2)

y - 1 = +/-3x - 6

y = +/-3x - 6 + 1

y = +/- 3x - 5

Therefore, the equation of the asymptote is y = 3x - 5.

Learn more about Asymptote here: brainly.com/question/4138300

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3 0
1 year ago
Is this triangle an acute, obtuse, or a right?
Ivanshal [37]
Its an acute or an obtuse triangle
5 0
3 years ago
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A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what
cluponka [151]

<u>Problem</u>

A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?

<u>Work </u>

Probability = no. of favorable outcomes /total no. of outcomes

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5/20×6/19

<u>Answer</u>

3/20

So it is C.

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P+3/m=-1 solve for p
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Look in the file below

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3 years ago
Estimate the area under the graph of f(x) = 2 cos(x) from x = 0 to x = π/2 using four approximating rectangles and right and lef
I am Lyosha [343]
So hmm notice the picture below

you're simply being asked to, approximate the area, by using 4 rectangles, like in the graph, it doesn't have to be an exact value, just an approximation, based on the width and height of the rectangles, and getting  their area by that

those rectangles are 0.39 radian long, since if you split π/2 in 4 pieces, you get around that much, the last rectangle there is a bit smaller than 0.39.... but they don't have to be 4 rectangles of equal length

so, get the area of the rectangles, based on their width and height, and sum them up

7 0
3 years ago
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