Answer:
In mathematics, a theorem is a non-self-evident statement that has been proven to be true, either on the basis of generally accepted statements such as axioms or on the basis of previously established statements such as other theorems. A theorem is hence a logical consequence of the axioms, with a proof of the theorem being a logical argument which establishes its truth through the inference rules of a deductive system. As a result, the proof of a theorem is often interpreted as justification of the truth of the theorem statement. In light of the requirement that theorems be proved, the concept of a theorem is fundamentally deductive, in contrast to the notion of a scientific law, which is experimental.
Step-by-step explanation:
Answer:
b)The standard normal distribution has a mean of 0 and a standard deviation of 1, while a nonstandard normal distribution has a different value for one or both of those parameters.
Step-by-step explanation:
The standard normal distribution, ( and associated tables ) N (0,1) where 0 is the mean and 1 the standard deviation, is a model representative of all other nonstandard normal distribution. Therefore we apply such concepts and tebles in the solution of problems concerning normal distribution
Answer:
Decimal 0.333 to a fraction in simplest form is: 
Step-by-step explanation:
Given the decimal

Multiply and divide by 10 for every number after the decimal point.
There are three digits to the right of the decimal point, therefore multiply and divide by 1000.
Thus,

∵ 0.333×1000 = 333
Let us check if we can reduce the fraction 
For this, we need to find a common factor of 333 and 1000 in order to cancel it out.
But, first, we need to find the Greatest Common Divisor (GCD) of 333, 1000
<u>Greatest Common Divisor (GCD) : </u>
The GCD of a, b is the largest positive number that divides both a and b without a remainder.
Prime Factorization of 333: 3 · 3 · 37
Prime Factorization of 1000: 2 · 2 · 2 · 5 · 5 · 5
As there is no common factor for 333 and 1000, therefore, the GCD is 1.
Important Tip:
- As GCD is 1, therefore the fraction can not be simplified.
Therefore, decimal 0.333 to a fraction in simplest form is: 
We have been given that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each bounce. We are asked to find the total distance traveled by up and down from the time it was dropped from the window until the 25th bounce.
We will use sum of geometric sequence formula to solve our given problem.
, where,
a = First term of sequence,
r = Common ratio,
n = Number of terms.
For our given problem
,
and
.





Therefore, the ball will travel 100 meters and option B is the correct choice.