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Nookie1986 [14]
3 years ago
13

What is the difference between neutralization and saturation?

Chemistry
1 answer:
irina1246 [14]3 years ago
5 0
Neutralization deals with the buffering or neutralizing of acids and bases. You change the pH of either an acid or a base by adding H+ ions to a base solution or adding OH- ions by adding a base(alkali) to an acid solution. Ideally you are neutralizing either one to a neutral pH condition which is "7" on the pH scale.

Saturation on the other hand deals with how much solute (solid) you can disolve in a solvent. As you add solute to solution it can only disolve a certain amount before the solvent becomes "satutated" and no more solute will desolve into a homogenous blend with the solvent. You then see precepitants start coming out of solution and falling to the bottom of the container the solution is contained in.
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You mix 55 ml of 1.00 m silver nitrate with 25 ml of 1.06 m sodium chloride. what mass of silver chloride should you form?
enot [183]

AgNO3 + NaCl ---> AgCl(s) + NaNO3

find moles of each

mmol = M*V

mmol = 55*1 = 55 mmol of Ag+

mmol = 25 * 1.06 = 26.5 mmol of Cl-

then limitn greactant is Cl

we can produce up to 26.5 mmol of Agcl

<span>mass = mol*MW = (26.5 * 10^-3) *  143.32 = 3.7980 g of AgCl</span>

<span> </span>

6 0
3 years ago
CuCO3(s) + 2HCl(aq) → CuCl2(aq) + H2O(l) + CO2(g). Which statement correctly describes the substances in this reaction?
navik [9.2K]

So,

All you need to do is read the physical states ( ) to determine the answer.

CuCO3 is solid.

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CuCl2 is in aqueous solution.

H2O is liquid.

CO2 is gas.

It is then easy to see that option D is true.  CuCO3 is the solid reactant, and CO2 is the gas product.

4 0
3 years ago
Mercury orbits the sun at more than four times the speed of Saturn
Irina18 [472]

Answer:

Yes

Explanation:

8 0
4 years ago
Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.
k0ka [10]

Answer:

Empirical Formula:

The empirical formula of a compound is the simplest whole-number ratio of the numbers of the different atoms that compose the molecule of the compound. The empirical formula looks like a molecular formula.

C

2

H

2

and

C

H

are the molecular formula and the empirical formula of acetylene.

The Given Data

The mass of carbon in the compound:

m

C

=

40.6

g

The mass of hydrogen in the compound: {eq}m_H = 5.1 \ \rm...

6 0
3 years ago
Read 2 more answers
30 mL of 0.6 M HCl solution is neutralized with 90 mL NaOH solution. What is the concentration of the base? Show all work Please
skad [1K]

From

<em>n</em><em>a</em><em>=</em><em>1</em>

<em>n</em><em>b</em><em>=</em><em>1</em>

<em>V</em><em>a</em><em>=</em><em>3</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>V</em><em>b</em><em>=</em><em>9</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>M</em><em>a</em><em>=</em><em>0</em><em>.</em><em>6</em><em>M</em>

<em>M</em><em>b</em><em>=</em><em>?</em>

<em>f</em><em>r</em><em>o</em><em>m</em>

<em>Mb</em><em>=</em><em><u>M</u></em><em><u>a</u></em><em><u>×</u></em><em><u>V</u></em><em><u>a</u></em><em><u>×</u></em><em><u>n</u></em><em><u>b</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>V</em><em>b</em><em>×</em><em>n</em><em>a</em>

<em>M</em><em>b</em><em>=</em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>×</u></em><em><u>3</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em><em>×</em><em>1</em>

<em>m</em><em>b</em><em>=</em><em><u>1</u></em><em><u>8</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em>

<em>M</em><em>b</em><em>=</em><em>0</em><em>.</em><em>2</em><em>M</em>

<em>NaOH</em><em>=</em><em>4</em><em>0</em>

<em>F</em><em>r</em><em>o</em><em>m</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>m</em><em>o</em><em>l</em><em>a</em><em>r</em><em>i</em><em>t</em><em>y</em><em>×</em><em>m</em><em>r</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>0</em><em>.</em><em>2</em><em>×</em><em>4</em><em>0</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>8</em><em>g</em><em>/</em><em>m</em><em>o</em><em>l</em>

3 0
3 years ago
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