Answer:
Light waves travel in straight lines through a vacuum or a uniform medium. They vary only in wavelengths but they typically consist of periodic oscillations of both electric and magnetic fields. These are generated by charged particles that traverse through straight line in a vacuum.
Explanation:
Answer:

Explanation:
¡Hola!
En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:

Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):

Quiere decir que las moles de N2(g) que se agregaron son:

¡Saludos!
Hello Gary My Man!
Well, as you can clearly see
<span>The atomic number of an element is basically the number of protons it has. So yes, for every element this is different. Now, the mass number of an element as known, is the number of protons+the number of neutrons. So theoretically as we can see, this number should be a whole number, but since there are different isotopes (atoms of the same element with different numbers of neutrons) of each element, most periodic tables take account of that, so they often include decimals as seen.
So in Short, ALL</span> the atoms of a particular element have the SAME EXACT atomic number<span> (</span>number<span> of protons of course). The </span>atoms of different elements have very different numbers of protons. And of course, the MASS number of an atom is the TOTAL number as known, of protons and of course, the neutrons it contains in it.
I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
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-TheOneAboveAll :D
The answer is D only metals are shiny and highly malleable
<span>chemicals reacting are written on the left, what is formed is written on the right after the = sign
eg Copper + oxygen = copper oxide.
Hope this helps , mark as brainliest and say thanks THANKS..</span>