An engineer turns the temperature of a gas down, holding the volume constant at 1,250 L. Initially, the temperature of the gas w
as 625. °C and had a pressure of 275. KPa. Determine the pressure of the gas when the temperature decreased to 240°C
1 answer:
Answer:
625=275
240=x
625x=275×240
625x=66000
x=66000/625
x=105 .6
Explanation:
If 625°C gives us 275KPa then 240°C will give us the the sum of 275×240 divided by 625
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