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2 years ago

Air is warmed and moisten as it moves through both the mouth and nasal passages.

Physics

2 answers:

Serggg [28]2 years ago

8 0

Answer: The given statement is true.

Transport of oxygen from the air takes place through respiratory system. Oxygen from air ( that is taken from the atmosphere) enters via a system of tubes, into our lungs and then it is released into the bloodstream ( to serve in various organs) whereas opposite route is followed by CO2 ( carbon dioxide).

In the respiratory tract, the nose is lined by mucosal epithelium that possessed glands ( which secrete thick mucus). Due to this, air is moistened. Beneath the epithelium surface, there lies network of blood vessels that help in warming the nasal cavity and thus the air is warmed.

Alexxx [7]2 years ago

3 0

Well, in my own personal case, I can actually move the air in either
direction through both of those.

When I move the air inward from the outside, it's warmed and moistened.

When I move it outward from the inside, it's not.

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Identifying Advantages of Parallel Circuits

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Answer: If one bulb goes out the other bulbs stay lit.

If there is a break in one branch of the circuit, current can still flow through the other branches.

Explanation:

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2 years ago

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A positive force on the balance indicates a downward force on the silver sphere while a negative force on the balance indicates

anastassius [24]

The two spheres have opposite charges.

<h3 /><h3 /><h3>What are types charge?</h3>

A charge can be negatively charged or positively charged.

When two charges have opposite signs, that is positive and negative signs, the two charges will attract each other.
When the two charges have the same sign, it causes repulsion.

When a positive charge points downwards ↓ and the negative charge points upwards ↑, this causes attraction and shows that the two charges are different.

Thus, we can conclude that the two spheres have opposite charges.

Learn more about attraction and repulsion of charges here: brainly.com/question/2396080

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2 years ago

Let A^=6i^+4j^_2k^ and B= 2i^_2j^+3k^. find the sum and difference of A and B

andreyandreev [35.5K]

Explanation:

Let $\textbf{A} = 6\hat{\textbf{i}} + 4\hat{\textbf{j}} - 2\hat{\textbf{k}}$ and $\textbf{B} = 2\hat{\textbf{i}} - 2\hat{\textbf{j}} + 3\hat{\textbf{k}}$

The sum of the two vectors is

$\textbf{A + B} = (6 + 2)\hat{\textbf{i}} + (4 - 2)\hat{\textbf{j}} + (-2 + 3)\hat{\textbf{k}}$

$= 8\hat{\textbf{i}} + 2\hat{\textbf{j}} + \hat{\textbf{k}}$

The difference between the two vectors can be written as

$\textbf{A - B} = (6 - 2)\hat{\textbf{i}} + (4 - (-2))\hat{\textbf{j}} + (-2 - 3)\hat{\textbf{k}}$

$= 4\hat{\textbf{i}} + 6\hat{\textbf{j}} - 5\hat{\textbf{k}}$

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3 years ago

A small water pump is used in an irrigation system. The pump takes water in from a river at 10oC, 100 kPa at a rate of 5 kg/s. T

sergij07 [2.7K]

Answer:

0.98kW

Explanation:

The conservation of energy is given by the following equation,

$\Delta U = Q-W$

$\dot{m}(h_1+\frac{1}{2}V_1^2+gz_1)-\dot{W} = \dot{m}(h_2+\frac{1}{2}V_2^2+gz_)$

Where

$\dot{m} =$ Mass flow

$h_1 =$ Specific Enthalpy (IN)

$h_2 =$ Specific Enthalpy (OUT)

$g =$ Gravity

$z_{1,2} =$ Heigth state (In, OUT)

$V_{1,2} =$ Velocity (In, Out)

Our values are given by,

$T_i = 10\°C$

$P_1 = 100kPa$

$\dot{m} = 5kg/s$

$z_2 = 20m$

For this problem we know that as pressure, temperature as velocity remains constant, then

$h_1 = h_2$

$V_1 = V_2$

Then we have that our equation now is,

$\dot{m}(gz_1) = \dot{m}(gz_2)+\dot{W}$

$\dot{W} = \frac{(5)(9.81)(0-20)}{1000}$

$\dot{W} = -0.98kW$

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3 years ago

An ice boat is coasting along a frozen lake. Friction between the ice and the boat is negligible, and so is air resistance. Noth

zhannawk [14.2K]

Answer:

(A) No

(B) Speed decreases

Explanation:

(A) since there is nothing propelling the boat and the friction between the ice and the boat and also air resistance is negligible the net force of the system in the horizontal direction is zero and hence there is no change in the horizontal momentum of the boat.

(B) Since the person had not velocity in the horizontal direction before landing on the boat but now has one after landing on the boat, the speed of the boat will decrease because the momentum has to be conserved (remember there is no change in it).

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3 years ago