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2 years ago

A mimibus drives with a constant speed of 39 km/h. how far can it travel in 1.94 hours?

Physics

1 answer:

Rufina [12.5K]2 years ago

4 0

Answer:

<em>The minibus traveled 75.66 km</em>

Explanation:

<u>Motion with Constant Speed </u>

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

The formula to calculate the speed is:

$\displaystyle v=\frac{d}{t}$

Where

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

From the equation above, we solve for d:

d = v . t

The minibus has a constant speed of v=39 km/h and it's required to find the distance it travels in t=1.94 hours.

Calculating the distance:

d = 39 km/h * 1.94 h

d = 75.66 km

The minibus traveled 75.66 km

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3 years ago

Someone help please by providing work and answers please :)

cupoosta [38]

There are two ways to solve this. The longer way is to use those equations to calculate numbers for total distance.

The easier way is to find the area under the graph. That's right, AREA UNDER VELOCITY-TIME graph is the TOTAL DISTANCE travelled!

it's a shortcut.

Let's split up the area into a triangle and rectangle:

Triangle = 0.5(4-0)(10-0) = 20 m
Rectangle = (6-4)(10-0) = 20 m

Total distance = 40 m!

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3 years ago

Please help it’s urgent

Sidana [21]

Answer:

I believe it's sound energy.

Explanation:

Sound can move through air, whereas electric and radiant energy don't have to.

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3 years ago

in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's

GarryVolchara [31]

The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.

<h3>What is the Inverse Square Law formula?</h3>

The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

Where

I₁ = Intensity at distance 1 (W/m²)
I₂ = Intensity at distance 2 (W/m²)
d₁ = distance 1 from a light source (m)
d₂ = distance 2 from a light source (m)

Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?

By using the inverse square law formula, the sun's intensity for an outer planet is

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

$\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}$