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musickatia [10]
3 years ago
9

How did potential energy get stored in the spring/pom pom system?

Physics
1 answer:
KengaRu [80]3 years ago
4 0

The elastic potential energy of a spring is the energy stored in the spring due to its elastic nature.

The potential energy stored in a spring is known as elastic potential energy. The elastic potential energy of a spring is the energy stored in the spring due to its elastic nature.

For example, when a spring is compressed it acquires potential energy which will be converted to kinetic energy of the object impacted by the spring.

The elastic potential energy of spring is given as;

U_{x} = \frac{1}{2}kx^{2}

where;

  • k is the spring constant
  • x is the extension of the spring.

Thus, we can conclude that, the elastic potential energy of a spring is the energy stored in the spring due to its elastic nature.

Learn more here: brainly.com/question/17717335

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A student was given a sample of crude acetanilide to recrystallize. The initial mass of the the crude acetanilide was 166 mg. Th
padilas [110]

Answer:

The percentage of mass recover from recrystallization = 24.69 %

Explanation:

Given that

Initial mass of crude acetanilide = 166 gm

The mass after recrystallization = 125 gm

The mass recover from recrystallization= 166 - 125 gm

The mass recover from recrystallization= 41 gm

The percentage of mass recover from recrystallization can be find as

percentage\ of\ mass\ recover\ from\ recrystallization\ =\dfrac{166-125}{166}

The percentage of mass recover from recrystallization = 24.69 %

4 0
3 years ago
Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a larg
valentina_108 [34]

Answer:

-time it takes for the sled to come to a stop after launch of rocket = 7.244 s

-distance sled has travelled from its starting point by the time it finally comes to rest is = 234.8655 m

Explanation:

From the question, looking at the motion while accelerating, we have;

Initial velocity; u = 0 m/s

Acceleration; a = 13.5 m/s²

Time; t = 3.3 s

Let's use first equation of motion to find final velocity (v).

v = u + at

v = 0 + (13.5 × 3.3)

v = 44.55 m/s

In this forward direction, let's calculate the displacement(d1) using newton's 3rd equation of motion.

d1 = ut + ½at²

d1 = 0(3.3) + ½(13.5 × 3.3²)

d1 = 73.5075 m

Now, let's consider the motion while slowing down and our final velocity will be 0 m/s while initial velocity will now be 44.55 m/s while acceleration is 6.15 m/s².

Thus, from v = u + at, we can find the time it take for the sled to come to a stop.

Now, since it's coming to rest acceleration will be negative. Thus;

0 = 44.55 + (-6.15t)

0 = 44.55 - 6.15t

t = 44.55/6.15

t = 7.244 s

Now we want to find out how far the sled has travelled from its starting point by the time it finally comes to rest.

Thus, we'll use the equation;

v² = u² + 2as

Where s will be the second displacement which we will call d2.

Thus;

0² = 44.55² + (-2 × 6.15 × s)

0 = 1984.7025 - 12.3s

12.3s = 1984.7025

s = 1984.7025/12.3

s = 161.358

Thus, d2 = s = 161.358 m

Thus, distance sled has travelled from its starting point by the time it finally comes to rest is ;

= d1 + d2 = 73.5075 + 161.358 = 234.8655 m

4 0
4 years ago
Light with a photon energy of 3 ev impinges on the surface of a material with work function 0.6 ev to eject electrons. what is t
DENIUS [597]

Answer:

KE = incident energy - work function

The maximum KE will be (3 - .6) eV = 2.4 eV

5 0
2 years ago
A ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10
irina [24]
First I’ll show you this standard derivation using conservation of energy:
Pi=Kf,
mgh = 1/2 m v^2,
V = sqrt(2gh)
P is initial potential energy, K is final kinetic, m is mass of object, h is height from stopping point, v is final velocity.
In this case the height difference for the hill is 2-0.5=1.5 m. Thus the ball is moving at sqrt(2(10)(1.5))=
5.477 m/s.
5 0
3 years ago
Read 2 more answers
Which is the force that results from use of a machine?
Goshia [24]

Answer:

D. Output force

Explanation:

The input force is the effort used to run the machine and this results in an output force.

3 0
2 years ago
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