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musickatia [10]
3 years ago
9

How did potential energy get stored in the spring/pom pom system?

Physics
1 answer:
KengaRu [80]3 years ago
4 0

The elastic potential energy of a spring is the energy stored in the spring due to its elastic nature.

The potential energy stored in a spring is known as elastic potential energy. The elastic potential energy of a spring is the energy stored in the spring due to its elastic nature.

For example, when a spring is compressed it acquires potential energy which will be converted to kinetic energy of the object impacted by the spring.

The elastic potential energy of spring is given as;

U_{x} = \frac{1}{2}kx^{2}

where;

  • k is the spring constant
  • x is the extension of the spring.

Thus, we can conclude that, the elastic potential energy of a spring is the energy stored in the spring due to its elastic nature.

Learn more here: brainly.com/question/17717335

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If gravity on the earth increased, what affect would it have on the moon
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6 0
3 years ago
A spring is compressed between two objects with unequal masses, m and M, ad held together. The objects are initially at rest on
AlekseyPX

Answer:

Explanation:

The complete question is here.

A spring is compressed between two objects with unequal masses, m and M, held together. The objects are initially at rest on a horizontal friction less surface. When released, which of the following is true?

a) Kinetic energy is same as before being released

b) The total final kinetic energy is zero.

c) The two objects have equal kinetic energy.

d) The speed of one object is equal to the speed of other.

e) The total final momentum of two objects is zero.

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5 0
4 years ago
Why do mass numbers have a trailing decimal? use the following words describe for credit isotopes protons neutrons electrons in
Dmitry_Shevchenko [17]

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Explanation:

3 0
4 years ago
A rocket car is developed to break the land speed record along a salt flat in Utah. However, the safety of the driver must be co
Naddika [18.5K]

Answer:

a = 45 m/s/s

Explanation:

As we know that total mass of the rocket is

M = 6000 kg

total mass of the fuel is given as

m = 2000 kg

all the fuel is burnt in 15 s

so rate of the fuel burning is given as

\frac{dm}{dt} = \frac{2000}{15}

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now the thrust force on the rocket is given as

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(6000 - 133.33 t) a = (900 + v)(133.33)

so we have

\frac{dv}{900 + v} = (133.33)\frac{dt}{6000 - 133.33 t}

so we have

ln(\frac{900 + v}{900}) = - ln(\frac{6000 - 133.3 t}{6000})

1 + \frac{v}{900} = \frac{6000}{6000 - 133.3 t}

now acceleration is rate of change in velocity

\frac{1}{900}\frac{dv}{dt} = \frac{133.3\times 6000}{(6000 - 133.3t)^2}

so acceleration at t = 15 s

a = 45 m/s^2

3 0
4 years ago
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