Answer:
THWB WB WQI B BW W;QQ QY G VQ Q VQVY VAV G UQ U
Explanation:QCGQ G GQUIGI QGUI; V AYDFYAFQAVAVY,
The sphere has a constant potential. It is the electric field.
![E = V_{0} = 0](https://tex.z-dn.net/?f=E%20%3D%20V_%7B0%7D%20%3D%200)
In the sphere, then
![E_{x} = 0, E_{y}=0, E_{z}=0](https://tex.z-dn.net/?f=E_%7Bx%7D%20%3D%200%2C%20%20E_%7By%7D%3D0%2C%20%20%20E_%7Bz%7D%3D0)
Outside the sphere, then
![V = V_{0} - E_{0}z + \frac{E_{0}a^{3}z}{(x^{2} +y^{2} + z^{2})^{3/2} }](https://tex.z-dn.net/?f=V%20%3D%20V_%7B0%7D%20-%20E_%7B0%7Dz%20%2B%20%5Cfrac%7BE_%7B0%7Da%5E%7B3%7Dz%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%20%2B%20z%5E%7B2%7D%29%5E%7B3%2F2%7D%20%20%20%7D)
The elements of the electric field include
![E_{x} =\frac{3E_{0}a^{3}xy}{(x^{2} +y^{2} +z^{2})^{5/2}}\\E_{y} = \frac{3E_{0}a^{3}xz}{(x^{2} +y^{2}+z^{2})^{5/2}}](https://tex.z-dn.net/?f=E_%7Bx%7D%20%3D%5Cfrac%7B3E_%7B0%7Da%5E%7B3%7Dxy%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%20%2Bz%5E%7B2%7D%29%5E%7B5%2F2%7D%7D%5C%5CE_%7By%7D%20%3D%20%5Cfrac%7B3E_%7B0%7Da%5E%7B3%7Dxz%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%2Bz%5E%7B2%7D%29%5E%7B5%2F2%7D%7D)
Which becomes,
![=E_{0} (1-\frac{a^{3}}{x^{2} +y^{2}+z^{2})^{3/2}}+\frac{3a^{3}z^{2}}{(x^{2} +y^{2}+z^{2})^{5/2}})](https://tex.z-dn.net/?f=%3DE_%7B0%7D%20%281-%5Cfrac%7Ba%5E%7B3%7D%7D%7Bx%5E%7B2%7D%20%2By%5E%7B2%7D%2Bz%5E%7B2%7D%29%5E%7B3%2F2%7D%7D%2B%5Cfrac%7B3a%5E%7B3%7Dz%5E%7B2%7D%7D%7B%28x%5E%7B2%7D%20%2By%5E%7B2%7D%2Bz%5E%7B2%7D%29%5E%7B5%2F2%7D%7D%29)
<h3>
In a consistent electric field, is force constant?</h3>
Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.
If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).
A torque is experienced by an electric dipole (p) in an even electric field (E). The vector cross product of p and E determines the torque's direction.
To learn more about uniform electric field, visit
brainly.com/question/17426130
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Answer:
E = 8.5 * 10^6 V/m
Explanation:
In general we have the following relation between the Electric Field and the Elecric Potential:
![\int\limits^2_1 {\vec{E} \cdot\vec{dl}} = V_{2} -V_{1}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_1%20%7B%5Cvec%7BE%7D%20%5Ccdot%5Cvec%7Bdl%7D%7D%20%3D%20V_%7B2%7D%20-V_%7B1%7D)
Due to the vector nature of the electric filed, we can only know the mean Electric field E across the membrane, and take it out from the integral, that is:
E = (ΔV)/L
Where L is the thickness of the membrane and ΔV is the potential difference.
Therefore:
E = 8.53933*10^6 V/m
rounding to the first tenth:
E = 8.5 * 10^6 V/m
It would be D I believe! Depending on the angle of the mirror and distance positioned!