31.79 g Cu / 63.5 g/mol Cu ---> 0.5
0.5 * (2/1) ---> 1
1 * 107.9 g/mol Ag
107.9 grams
Answer: Use Avogadro's number, NA = 6.02 × 1023 atoms/mol.
Explanation:
Answer:
The density is 10.25 ![\frac{atom}{nm^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Batom%7D%7Bnm%5E%7B2%7D%20%7D)
Explanation:
From the question we are given that the lattice spacing nm
V =
× ![nm^{3}](https://tex.z-dn.net/?f=nm%5E%7B3%7D)
= 0.1628 ![nm^{3}](https://tex.z-dn.net/?f=nm%5E%7B3%7D)
zinc blende lattice has 4 atom per unit cell.
This means that 4 atoms is contained in 0.15056 ![nm^{3}](https://tex.z-dn.net/?f=nm%5E%7B3%7D)
Density of the cubic unit in terms of atom is given as =
=26.565 ![\frac{atoms}{nm^{3} }](https://tex.z-dn.net/?f=%5Cfrac%7Batoms%7D%7Bnm%5E%7B3%7D%20%7D)
For plane (110) the spacing between the cubic unit in the crystal denoted by
is given as =
Where a is the lattic spacing = 0.546
=
= 0.376 nm
The density of the lattice in (110) plane =26.565
× 0.386 nm
= 10.25 ![nm^{2}](https://tex.z-dn.net/?f=nm%5E%7B2%7D)
Answer:
20
Explanation:
you multyply than divied than add